Milk milk milk........

Which of these is an accurate source of evidence for an investigation?

Feliz [49]

Answer:

observations

Explanation:

4 0

3 years ago

During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. S

Kay [80]

<u>Answer:</u> The below calculations proves that the rate of diffusion of $^{235}UF_6$ is 0.4 % faster than the rate of diffusion of $^{238}UF_6$

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of $^{235}UF_6=349.034348g/mol$

Molar mass of $^{238}UF_6=352.041206g/mol$

By taking their ratio, we get:

$\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{M_{(^{238}UF_6)}}{M_{(^{235}UF_6)}}}$

$\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{352.041206}{349.034348}}\\\\\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\frac{1.00429816}{1}$

From the above relation, it is clear that rate of effusion of $^{235}UF_6$ is faster than $^{238}UF_6$

Difference in the rate of both the gases, $Rate_{(^{235}UF_6)}-Rate_{(^{238}UF_6)}=1.00429816-1=0.00429816$

To calculate the percentage increase in the rate, we use the equation:

$\%\text{ increase}=\frac{\Delta R}{Rate_{(^{235}UF_6)}}\times 100$

Putting values in above equation, we get:

$\%\text{ increase}=\frac{0.00429816}{1.00429816}\times 100\\\\\%\text{ increase}=0.4\%$

The above calculations proves that the rate of diffusion of $^{235}UF_6$ is 0.4 % faster than the rate of diffusion of $^{238}UF_6$

3 0

3 years ago

Ow doe the respiratory system work? (Use 3-5 sentences to explain how the respiratory system works.)

Juliette [100K]

Answer:

The respiratory system is a system in your body that is in charge of helping you breathe. the respiratory system is made up of airways, lungs, and blood vessels, these parts work together to get oxygen into your body. Our respiratory system is a vital system, as it lets us live and breathe.

Explanation:

Here you go, don't copy exactly

7 0

3 years ago

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BIG POINTS! NO SPAM PLZ! WILL AWARD BRAINLIEST!

pentagon [3]

Answer:

1.0 M is the concentration of hydrochloric acid.

Explanation:

$HCl (aq) + NaOH (aq) \rightarrow H_2O (l) + NaCl (aq)$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?\\V_1=50.0 mL\\n_2=1\\M_2=2.0 M\\V_2=25.0 mL$

Putting values in above equation, we get:

$1\times M_1\times 50.0 mL=1\times 2.0 M\times 25.0 mL$

$M_1=\frac{1\times 2.0 M\times 25 mL}{1\times 50.0 mL}=1.0M$

1.0 M is the concentration of hydrochloric acid.

6 0

3 years ago

Which represents the balanced equation for the beta minus emission of phosphorus-32? Superscript 32 subscript 15 upper P right a

Ede4ka [16]

Answer: Superscript 32 subscript 15 upper P right arrow superscript 32 subscript 16 upper S plus superscript 0 subscript negative 1 e.

Explanation:

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.

The general representation of beta minus emission is :

$_A^Z\textrm{X}\rightarrow _{A+1}^Z\textrm{Y}+_{-1}^0e$

The representation of beta decay of phosphorous- 32 :

$_{15}^{32}\textrm{P}\rightarrow _{16}^{32}\textrm{S}+_{-1}^0e$

Superscript 32 subscript 15 upper P right arrow superscript 32 subscript 16 upper S plus superscript 0 subscript negative 1 e.

8 0

3 years ago