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Ierofanga [76]
3 years ago
7

You are sharing a house with a few roommates. One of them plays on the basketball team, and is exactly 200 cm tall. The heights

of you and the other roommates are 188 cm, 175 cm, and 160 cm. You want to buy the minimum height mirror that will allow all of you to see your entire selves, when the mirror is mounted in a fixed position on the wall. Assume each person's eyes are at a level 95% of their height. How tall a mirror should you buy
Physics
1 answer:
Advocard [28]3 years ago
8 0

Answer:

119 cm

Explanation:

Given heights :  200cm , 188 cm , 175 cm, 160 cm

since the eyes are at 95% level

95% of 200 cm = 190 cm

95% of 160 cm = 152 cm

hence the allowable height of mirror = 200 - ( 5 + 76 ) = 119 cm

and The mirror should be hung 75cm from the floor

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Suppose that on a hot and sticky afternoon in the spring, a tornado passes over the high school. If the air pressure in the lab
forsale [732]

Answer:

232.9m³ (Option b. is the closest answer)

Explanation:

Given:

Air pressure in the lab before the storm, P₁ = 1.1atm

Air volume in the lab before the storm, V₁ = 180m³

Air pressure in the lab during the storm P₂ = 0.85atm

Air volume in the lab before the storm, V₂ = ?

Applying Boyle's law:    P₁V₁ = P₂V₂    (at constant temperature)

                          V_{2} = \frac{P_{1}V_{1}}{P_{2}}

                          V_{2} = \frac{1.1 * 180}{0.85}

                          V_{2} = \frac{198}{0.85}

                           V₂  = 232.9m³

The air volume in the laboratory that would expand in order to make up for the large pressure difference outside is 232.9m³

7 0
3 years ago
A uniform string of length 10.0 m and weight 0.32 N is attached to the ceiling. A weight of 1.00 kN hangs from its lower end. Th
Juliette [100K]

Answer: 0.0180701 s

Explanation:

Given the following :

Length of string (L) = 10 m

Weight of string (W) = 0.32 N

Weight attached to lower end = 1kN = 1×10^3

Using the relation:

Time (t) = √ (weight of string * Length) / weight attached to lower end * acceleration due to gravity

g = acceleration due to gravity = 9.8m/s^2

Weight of string = 0.32N

Time(t) = √ (0.32 * 10) / [(1*10^3) * (9.8)]

Time = √3.2 / 9800

= √0.0003265

= 0.0180701s

5 0
3 years ago
If the temperature is held constant during this process and the final pressure is 683 torrtorr , what is the volume of the bulb
Anna [14]

Answer:

Explanation:

Let the volume of the unknown bulb = X L

The volume of the system , after opening valve = (X + 0.72 L )

Use Boyles law gas equation,

P1V1 = P2V2 ( at temperature is constant )

Given:

P1 = 1.2 atm

P2 = 683 torr

Converting mmHg to atm,

1 atm = 760 mmHg(torr)

683 mmHg = 683/760

= 0.8987 atm

1.2X = 0.8987*(X + 0.720)

1.2X = 0.8987X + 0.6471

0.3013X = 0.6471

X = 2.15 L

5 0
3 years ago
A 46.8-g golf ball is driven from the tee with an initial speed of 58.8 m/s and rises to a height of 24.7 m. (a) Neglect air res
Andre45 [30]

Answer:

a) the kinetic energy of the ball at its highest point is 69.58 J

b) its speed when it is 8.11 m below its highest point is 55.97 m/s

Explanation:

Given that;

mass of golf ball m = 46.8 g = 0.0468 kg

initial speed of the ball v₁ = 58.8 m/s

height h = 24.7 m

acceleration due to gravity = 9.8 m/s²

the kinetic energy of the ball at its highest point = ?

from the conservation of energy;

Kinetic energy at the highest point will be;

K.Ei + P.Ei = KEf + PEf

now the Initial potential energy of the ball P.Ei = 0 J

so

1/2mv² + 0 J = KEf + mgh

K.Ef = 1/2mv² - mgh

we substitute

K.Ef = [1/2 × 0.0468 × (58.8 )²] - [0.0468 × 9.8 × 24.7]

K.Ef  = 80.904 - 11.3284

K.Ef = 69.58 J

Therefore, the kinetic energy of the ball at its highest point is 69.58 J

b) when the ball is 8.11 m below the highest point, speed = ?

so our raw height h' will be ( 24.7 m - 8.11 m) = 16.59 m

so our velocity will be v₂

also using the principle of energy conservation;

K.Ei + P.Ei = KEh + PEh

1/2mv² + 0 J = 1/2mv₂² + mgh'

1/2mv₂² = 1/2mv² - mgh'

multiply through by 2/m

v₂² = v² - 2gh'

v₂ = √( v² - 2gh' )

we substitute

v₂ = √( (58.8)² - 2×9.8×16.59 )

v₂ = √( 3457.44 - 325.164 )  

v₂ = √( 3132.276 )

v₂ = 55.97 m/s

Therefore, its speed when it is 8.11 m below its highest point is 55.97 m/s

5 0
3 years ago
Kinetic energy is the energy of
Alina [70]

Kinetic energy is the energy of motion.

The formula for kinetic energy is given as

KE = (0.5) m v²

where m = mass of object , v = speed of object.

an object having some speed and mass will have kinetic energy while an object at rest will not have any kinetic energy since the speed of object at rest is zero.

Since at rest speed is zero. an object has kinetic energy only when it is in motion.

3 0
3 years ago
Read 2 more answers
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