Answer:
4.2
Explanation:
The "allowance" is the difference between the maximum shaft size and the minimum hole size.
maximum shaft = C +D = 8.5 +0.1 = 8.6
minimum hole = A -B = 4.8 -0.4 = 4.4
Allowance = 8.6 -4.4 = 4.2
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For an interference fit, the allowance is negative.
Answer:
Maximum allowable chip power is 0.35 W
Explanation:
This question is incomplete. The complete question is
A square isothermal chip is of width w = 5 mm on a side and is mounted in a substrate such that its side and back surfaces are well insulated; the front surface is exposed to the flow of a coolant at t[infinity] = 15°c. from reliability considerations, the chip temperature must not exceed t = 85°c. f the coolant is air and the corresponding convection 200 w/m2 k, what is the maximum allowable chip power?
<u>ANSWER:</u>
The heat transfer through convection, we have the equation:
q = hA(T - T∞)
where,
q = power transfer through convection = ?
h = convection coefficient = 200 W/m²K
A = Area of convection surface = (0.005 m)² = 0.000025 m²
T = Chip surface temperature = 85° C
T∞ = Fluid temperature = 15° C
Therefore,
q = (200 W/m².K)(0.000025 m²)(85° C - 15° C)
<u>q = 0.35 W</u>
Since, difference in temperature is same on both Celsius and kelvin scale. Therefore, Celsius is written as kelvin for difference and they shall be cancelled.
I believe it is cold forging?
sorry this answer was very confusing.
Answer:
Replace the toner cartridge
Explanation:
solution
when laser printer print black color liner vertical line print it is very frustrating that condition nearly empty toner cartridge
but first we clean the corona wire for that color line
and Reinstall the toner cartridges after Shake the toner cartridge side to side
if problem not solve than Clean the drum unit
and finally if not solve change the toner cartridge
so as that our problem will be resolve
Answer:
t = 2212 years
Explanation:
In radioactive decay processes it is described by the equation
N = N₀ 
to calculate the activity
= log 2 /λ
λ = log 2 / T_{1/2}
λ = log 2 /5715
λ = 5.267 10⁻⁵
now the amount of carbon 14 is N₀ = 0.1%, the sample contains an amount of N = 0.089%
N / N₀ = e^{-\lambda t}
-λ t = ln N / N₀
t = - 1 /λ ln N /N₀
t = 1 / 5.267 10⁻⁵ ln (0.089 / 0.1)
t = 2,212 10³ years
t = 2212 years
