Answer:
A variable (often denoted by x ) whose variation does not depend on that of another.
Explanation:
This question is a big fat non sequitur !
The wavelength of radio waves traveling through vacuum only depends on the frequency that the radio station is licensed to broadcast on, (which had better be the frequency of the transmitter that they buy and use, or they're in big trouble).
The wavelength does NOT depend on the type of modulation that's used to put information onto the signal.
An amateur radio (ham) operator may very well start out using FM to talk over his radio to somebody else, and then for some reason they may decide to switch to AM. They can do that without ANY change in the wavelength of their transmissions.
Now, in the USA and many other countries, it so happens that all AM stations are licensed by their governments to transmit their programs on a channel somewhere between 500 KHz and 1.6 MHz, and all FM stations are licensed by their governments to transmit their programs on a channel somewhere between 88 MHz and 108 MHz. (And THAT's what the radio receivers in these countries are built to receive.)
Then we might say that all of the AM stations are grouped around 1 MHz, and all of the FM stations are grouped around 100 MHz. The FM frequencies are very roughly 100 times the AM frequencies, so the AM wavelengths are very roughly 100 times the FM wavelengths. That's <em>choice (3)</em> .
But please don't get the idea that it has anything to do with using AM or FM technology. It's just a matter of where in the spectrum the government decided to put the AM stations and where they put the FM stations.
For that matter . . . An analog TV station uses an AM signal for the picture and an FM signal for the sound, and it all goes in the same channel, with just about the same wavelengths !
Answer:
The process is not possible
Explanation:
if we want to determine if the process is possible , we can check with the second law of thermodynamics
ΔS≥ ∫dQ/T
for a constant temperature process ( condensation)
ΔS≥ 1/T ∫dQ
and from the first law of thermodynamics
ΔH = Q - ∫VdP , but P=constant → dP=0 → ∫VdP=0
Q=ΔH
then
ΔS≥ΔH/T
from steam tables
at P= constant = 200 Kpa → T= 120°C = 393 K
at P= constant → H vapor = 2201.5 kJ/kg , H liquid = 1.5302 kJ/kg
, S vapor= 7.1269 kJ/kg , S liquid 1.7022 kJ/kg
therefore
ΔH = H vapor - H liquid = 2201.5 kJ/kg - 1.5302 kJ/kg = 2199.9698 kJ/kg
ΔS = S vapor - S liquid = 7.1269 kJ/kg - 1.7022 kJ/kg = 5.4247 kJ/kg
therefore since
ΔS required = ΔH/T = 2199.9698 kJ/kg/(393 K)= 5.597 kJ/kg K
and
ΔS= 5.4247 kJ/kg ≤ ΔS required=5.597 kJ/kg K
the process is not possible
Answer:
It would take the cyclist 2 hours to cycle to school.
Explanation:
5km/hr for 2 hours would be 10km.
Complete Question
the maximum force a pilot can stand is about seven times his weight. what is the minimum radius of curvature that a jet plane's pilot, pulling out of a vertical dive, can tolerate at a speed of 250m/s?
Answer:
The value is 
Explanation:
From the question we are told that
The weight of the pilot is 
The maximum force a pilot can withstand is 
The speed is 
Generally the centripetal force acting on the pilot is equal to the net force acting on the pilot i.e
Here N is the normal force acting on the pilot
Now
So
=> 
=>
=> 
