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Nadya [2.5K]
3 years ago
13

Thermal energy always moves from ___ to ___

Chemistry
2 answers:
Elza [17]3 years ago
8 0

Answer:

higher to lower temp

Explanation:

I need something here

Inessa05 [86]3 years ago
5 0

Answer:

hot to cold

Explanation:

pls mark brainliest

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PLEASE HELP !!!!
SpyIntel [72]

Answer:

Volume

Explanation:

A cubic centimeters(cm³) is a measure of volume that is equal to a cube with width, length and height are all 1 centimeters. then, multiply length, width and height values together, this will give you the volume of the cube. 1 inch = 2.54 centimeters

7 0
3 years ago
Calculate ΔH∘f (in kilojoules per mole) for benzene, C6H6, from the following data: 2C6H6(l) + 15O2(g)→12CO2(g)+6H2O(l) ΔH∘=−653
Pachacha [2.7K]

Answer: 48.6 kJ/mol

Explanation:

The balanced chemical reaction is,

2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(l)

The expression for enthalpy change is,

\Delta H=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

\Delta H=[(n_{CO_2}\times \Delta H_{CO_2})+(n_{H_2O}\times \Delta H_{H_2O})]-[(n_{O_2}\times \Delta H_{O_2})+(n_{C_6H_6}\times \Delta H_{C_6H_6})]

where,

n = number of moles

\Delta H_{O_2}=0 (as heat of formation of substances in their standard state is zero

Now put all the given values in this expression, we get

-6534.0=[(12\times -393.5)+(6\times -285.8)]-[(15\times 0)+(2\times \Delta H_{C_6H_6})]

\Delta H_{C_6H_6}=48.6kJ/mol

Therefore, the enthalpy change for benzene is 48.6 kJ/mol

4 0
3 years ago
Need help with this asap please.
Naddik [55]

Answer:

its upside down

Explanation:

4 0
3 years ago
a sample of CO2 occupies a volume of 280ml at a pressure of 1.3 atm and a temperature of 18 degrees celsius, what volume will th
monitta

We can calculate the new volume of the gas using the Combined Gas Law:

(P1 x V1) / T1 = (P2 x V2) / T2

The initial volume, pressure, and temperature were 280 mL, 1.3 atm, and 291.15 K (changing the temperature into Kelvin is necessary), and the final volume, pressure, and temperature is V2, 3.0 atm, and 308.15 K. Plugging these values in and solving, we find that:

(P1 x V1) / T1 = (P2 x V2) / T2

(1.3 atm x 280 mL) / 291.15 K = (3.0 atm x V2) / 308.15 K

V2 = 128.42 mL

This makes sense considering the conditions, a small increase in temperature would make the gas expand but a significant increase in the pressure would cause the volume to decrease.

Hope this helps!

7 0
3 years ago
Can anyone help me with these I’m really co fused on what to do it’s for chemistry?
liq [111]

Answer:

It's just asking you to rearrange to equations to get what you want, so no numbers involved it's just teaching you the basics.

Explanation:

3 0
4 years ago
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