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If a source of waves produces 30 waves per second, what is the frequency in hertz?

sukhopar [10]

Answer:

30hz is the answer for the question

3 0

2 years ago

Un the way to the moon, the Apollo astro-

kherson [118]

Answer:

Distance = 345719139.4[m]; acceleration = 3.33*10^{19} [m/s^2]

Explanation:

We can solve this problem by using Newton's universal gravitation law.

In the attached image we can find a schematic of the locations of the Earth and the moon and that the sum of the distances re plus rm will be equal to the distance given as initial data in the problem rt = 3.84 × 108 m

$r_{e} = distance earth to the astronaut [m].\\r_{m} = distance moon to the astronaut [m]\\r_{t} = total distance = 3.84*10^8[m]$

Now the key to solving this problem is to establish a point of equalisation of both forces, i.e. the point where the Earth pulls the astronaut with the same force as the moon pulls the astronaut.

Mathematically this equals:

$F_{e} = F_{m}\\F_{e} =G*\frac{m_{e} *m_{a}}{r_{e}^{2} } \\$

$F_{m} =G*\frac{m_{m}*m_{a} }{r_{m} ^{2} } \\where:\\G = gravity constant = 6.67*10^{-11}[\frac{N*m^{2} }{kg^{2} } ] \\m_{e}= earth's mass = 5.98*10^{24}[kg]\\ m_{a}= astronaut mass = 100[kg]\\m_{m}= moon's mass = 7.36*10^{22}[kg]$

When we match these equations the masses cancel out as the universal gravitational constant

$G*\frac{m_{e} *m_{a} }{r_{e}^{2} } = G*\frac{m_{m} *m_{a} }{r_{m}^{2} }\\\frac{m_{e} }{r_{e}^{2} } = \frac{m_{m} }{r_{m}^{2} }$

To solve this equation we have to replace the first equation of related with the distances.

$\frac{m_{e} }{r_{e}^{2} } = \frac{m_{m} }{r_{m}^{2} } \\\frac{5.98*10^{24} }{(3.84*10^{8}-r_{m} )^{2} } = \frac{7.36*10^{22} }{r_{m}^{2} }\\81.25*r_{m}^{2}=r_{m}^{2}-768*10^{6}* r_{m}+1.47*10^{17} \\80.25*r_{m}^{2}+768*10^{6}* r_{m}-1.47*10^{17} =0$

Now, we have a second-degree equation, the only way to solve it is by using the formula of the quadratic equation.

$r_{m1,2}=\frac{-b+- \sqrt{b^{2}-4*a*c } }{2*a}\\ where:\\a=80.25\\b=768*10^{6} \\c = -1.47*10^{17} \\replacing:\\r_{m1,2}=\frac{-768*10^{6}+- \sqrt{(768*10^{6})^{2}-4*80.25*(-1.47*10^{17}) } }{2*80.25}\\\\r_{m1}= 38280860.6[m] \\r_{m2}=-2.97*10^{17} [m]$

We work with positive value

rm = 38280860.6[m] = 38280.86[km]

Second part

The distance between the Earth and this point is calculated as follows:

re = 3.84 108 - 38280860.6 = 345719139.4[m]

Now the acceleration can be found as follows:

$a = G*\frac{m_{e} }{r_{e} ^{2} } \\a = 6.67*10^{11} *\frac{5.98*10^{24} }{(345.72*10^{6})^{2} } \\a=3.33*10^{19} [m/s^2]$

6 0

3 years ago

What are the seasonal changes in the weasel in florida and the weasel in wyoming

AlekseyPX

Winter weasels, also called ermines or short-tailed weasels, have coats that turn from light brown to white in the winter. The color change begins at their stomachs and works its way outward, occurring in both spring and fall. Other species, like the long-tailed weasel, may turn at least partially white as well.

The length of daylight, not temperature, prompts the color change. As a result, weasels in winter may be stark white against a brown landscape before snow starts to fall. During warmer winters, this makes them easy prey for larger predators such as foxes, martens, and badgers.

7 0

3 years ago

A car is traveling south at a speed of 52 miles per hour and then begins traveling at a speed of 53 miles per hour but continues

gregori [183]

It has to be velocity

7 0

3 years ago

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Two masses are separated by a distance r. If this distance is doubled, is the force of interaction between the two masses double

baherus [9]

Newton's law of universal gravitation states that every particle attracts every other particle in the universe with a force which is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

This is mathematically represented as

F= (G X m1 x m2) /r∧2

where F is the force acting between the charged particles

r is the distance between the two charges measured in m

G is the gravitational constant which has a value of 6.674×10^-11 Nm^2 kg^-2

m1 and m2 are the masses of the objects measured in Kg

Now if the distance between the is doubled then r becomes 2r. Substituting this in the above formula we get the new Force as

Force (new) = (G X m1 x m2) /(2r)∧2

Thus dividing Force(new)/Force we get

Force(new)/Force = 1/4.

Thus the gravitational force becomes 1/4th of the original value if the distance between the two masses are doubled.

7 0

3 years ago

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