Answer
given,
Hunk Finn speed,v_y= 0.7 m/s
Speed of river,v_x = 1.50 m/s
Assuming the speed of the river is in x-direction.
Speed of Hunk Finn to be in y-direction.
Hunk velocity relative to river =
Speed of Hunk relative to river = 1.66 m/s
direction of the boat
Hence, angle of the raft is 24.01°
Answer:
6.0 s
98 m/s
Explanation:
The radius of the planet is much bigger than the height of the tower, so we will assume the acceleration is constant. Neglect air resistance.
Acceleration due to gravity on this planet is:
a = GM / r²
a = (6.67×10⁻¹¹ m³/kg/s²) (2.7 × 1.48×10²³ kg) / (1.7 × 750,000 m)²
a = 16.4 m/s²
The height of the tower is:
Δy = 96 × 3.05 m
Δy = 293 m
Given v₀ = 0 m/s, find t and v.
Δy = v₀ t + ½ at²
(293 m) = (0 m/s) t + ½ (16.4 m/s²) t²
t = 6.0 s
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (16.4 m/s²) (293 m)
v = 98 m/s
It’s red shift and blue shift because This only occurs when the frequency of the wave is made longer or shorter due to the movement of the source relative to the observer
From the calculations, the final momentum of B is 8.16 m/s
<h3>What is conservation of linear momentum?</h3>
According to the principle of the conservation of linear momentum, the momentum before collision is equal to the total momentum after collision.
This implies that;
MaUa + MbUb = MaVa + MaVa
Substituting values;
(0.08 kg * 0.5 m/s) + (0.05 kg * 0 m/s) = (0.08 kg * −0.1 m/s) + (0.05 kg * v)
0.4 = -0.008 + 0.05v
v = 8.16 m/s
Learn more about more about momentum: brainly.com/question/24030570:
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Answer:
The net forces exerted on the horse and cart are not the same, so they are not balanced forces.
Explanation:
Using newton laws,
ΣF = ma
The two forces acting on the body is the forward force by the horse and the frictional force opposing the forward force
F-Fr= ma
Therefore,
F=ma+Fr
So the forward (by horse) is more than the opposite reaction (by cart).
The only time the forward force and the opposite reaction are the same is when a=0, I.e, the body is not moving at all or the body is moving at constant velocity.
