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max2010maxim [7]
3 years ago
11

Why is nut-cracker 2nd class lever?​

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
4 0

2nd class leaver refers to such leaver in which load lies between effort and fulcrum.In a nut cracker too load is in between effort and fulcrum.Thus, nut cracker is a 2nd class leaver.......

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Calculate the ratio of the resistance of 12.0 m of aluminum wire 2.5 mm in diameter, to 30.0 m of copper wire 1.6 mm in diameter
alukav5142 [94]

Answer: 0.258

Explanation:

The resistance R of a wire is calculated by the following formula:

R=\rho\frac{l}{s}    (1)

Where:

\rho is the resistivity of the material the wire is made of. For aluminium is \rho_{Al}=2.65(10)^{-8}m\Omega  and for copper is \rho_{Cu}=1.68(10)^{-8}m\Omega

l is the length of the wire, which in the case of aluminium is l_{Al}=12m, and in the case of copper is l_{Cu}=30m

s is the transversal area of the wire. In this case is a circumference for both wires, so we will use the formula of the area of the circumference:

s=\pi{(\frac{d}{2})}^{2}  (2) Where d  is the diameter of the circumference.

For aluminium wire the diameter is  d_{Al}=2.5mm=0.0025m  and for copper is d_{Cu}=1.6mm=0.0016m

So, in this problem we have two transversal areas:

<u>For aluminium:</u>

s_{Al}=\pi{(\frac{d_{AL}}{2})}^{2}=\pi{(\frac{0.0025m}{2})}^{2}

s_{Al}=0.000004908m^{2}   (3)

<u>For copper:</u>

s_{Cu}=\pi{\frac{(d_{Cu}}{2})}^{2}=\pi{(\frac{0.0016m}{2})}^{2}

s_{Cu}=0.00000201m^{2}    (4)

Now we have to calculate the resistance for each wire:

<u>Aluminium wire:</u>

R_{Al}=2.65(10)^{-8}m\Omega\frac{12m}{0.000004908m^{2}}     (5)

R_{Al}=0.0647\Omega     (6)  Resistance of aluminium wire

<u>Copper wire:</u>

R_{Cu}=1.68(10)^{-8}m\Omega\frac{30m}{0.00000201m^{2}}     (6)

R_{Cu}=0.250\Omega     (7)  Resistance of copper wire

At this point we are able to calculate the  ratio of the resistance of both wires:

Ratio=\frac{R_{Al}}{R_{Cu}}   (8)

\frac{R_{Al}}{R_{Cu}}=\frac{0.0647\Omega}{0.250\Omega}   (9)

Finally:

\frac{R_{Al}}{R_{Cu}}=0.258  This is the ratio

3 0
3 years ago
If you can answer both, please do. But if you can't, just answer one.
Setler [38]

Answer:

1.The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

                                      p = m(u - v)

                                         = 7 (3.5 - 0)

                                         = 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

                                           F = p / t

                                               = 24.5 / 2

                                               = 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

2.

We have: F = m × v/t

Here, m = 8500 Kg

v = 20 m/s

t = 10 s

Substitute their values into the expression,  

F = 8500 × 20/10

F = 8500 × 2

F = 17000 N

In short, final answer would be 17000 N

Hope this helps!!

7 0
3 years ago
A small metal sphere weighs .28 N in air and has a volume of13
Ray Of Light [21]

To solve this problem we will start by considering how to calculate the apparent weight. On the sphere this will then be given that the real weight is the sum of the apparent weight and the Buoyant Force. Therefore we will have to

W_T = W_A + F_B

Here

W_T= True Weight

W_A= Apparent Weight

F_B= Buoyant Force

If we seek to find the apparent weight we will have to,

W_A = W_T-F_B

W_A = 0.28N - V\rho g

Remember that

V = Volume (Volume Sphere)

\rho= Density (At this case water density)

g = Gravitational acceleration

W_A = 0.28N - (13*10^{-6}m^3)(1000kg/m^3)(9.8)

W_A = 0.1526N

Therefore the apparent weight will be 0.1526N

5 0
4 years ago
Which is an example of convection currents?
Levart [38]
Answer:
B
Explanation:
because, convection is the transfer of heat between fluid substances/materials
8 0
3 years ago
Read 2 more answers
While a utility patent protects the way an invention is used and​ works, a​ ___ patent protects the way it looks?
AnnZ [28]
<span>While a utility patent protects the way an invention is used and​ works, a​ design patent protects the way it looks.
Patent is a grant from federal government conferring the rights to exclude others from making, using or selling an invention.
There are three types of patents: Utility, design and plant. Only the inventor or inventors together can apply for a patent.</span>
4 0
4 years ago
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