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3 years ago

Find the gram formula mass of each compound.

1 answer:

6 0

The gram formula mass is another term for the mass of one mole of the substance which can be calculated by adding up the masses of the elements comprising the formula unit, molecules, etc.

a. Barium Fluoride (BaF2)
m = mass of Ba + 2(mass of F)
m = 137.327 g + 2(19 g)
m = 175.327 g

b. Strontium Cyanide (Sr(CN)2)
m = mass of Sr + 2(mass of C) + 2(mass of N)
m = 87.62 + 2(12) + 2(14)
m = 139.62 g

c. Sodium hydrogen Carbonate (NaHCO3)
m = mass of Na + mass of H + mass of C + 3(mass of O)
m = 23 + 1 + 12 + 3(16)
m = 84 g

d. Aluminum sulfide (Al2S3)
m = 2(mass of Al) + 3(mass of S)
m = 2(26.98) + 3(32)
m = 149.96 g

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Which of the following compounds has the highest boiling point.

nlexa [21]

Answer:
1-Pentanol has the highest boiling point.

Explanation:
Boiling points of given compounds are as follow,

1) 2-Pentanone = 101 °C

2) 1-Pentanol = 138 °C

3) Pentane = 36.1 °C

4) Pentanal = 103 °C

Pentanol has greatest boiling point as compare to others because it involes a strongest intermolecular interactions called as hydrogen bond interactions. Remaining compounds lack the direct attachement of hydrogen to most electrnegative atom like oxygen which is present in 1-Pentanol.

4 0

3 years ago

A certain liquid has a normal boiling point of and a boiling point elevation constant . A solution is prepared by dissolving som

jek_recluse [69]

The question is incomplete, the complete question is:

A certain substance X has a normal freezing point of $-6.4^oC$ and a molal freezing point depression constant $K_f=3.96^oC.kg/mol$ . A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at $-13.6^oC$ . Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.

Answer: The mass of glycine that can be dissolved is $1.3\times 10^2g$

Explanation:

Depression in the freezing point is defined as the difference between the freezing point of the pure solvent and the freezing point of the solution.

The expression for the calculation of depression in freezing point is:

$\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m$

$\text{Freezing point of pure solvent}=\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times w_{solvent}\text{(in g)}}$ ......(1)

where,

Freezing point of pure solvent = $-6.4^oC$

Freezing point of solution = $-13.6^oC$

i = Vant Hoff factor = 1 (for non-electrolytes)

$K_f$ = freezing point depression constant = $3.96^oC/m$

$m_{solute}$ = Given mass of solute (glycine) = ?

$M_{solute}$ = Molar mass of solute (glycine) = 75.07 g/mol

$w_{solvent}$ = Mass of solvent = 950. g

Putting values in equation 1, we get:

$-6.4-(-13.6)=1\times 3.96\times \frac{m_{solute}\times 1000}{75.07\times 950}\\\\m_{solute}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\m_{solute}=129.66g=1.3\times 10^2g$

Hence, the mass of glycine that can be dissolved is $1.3\times 10^2g$

5 0

3 years ago

How many grams of oxygen are required to burn 0.10mole of c3h8?

Anastaziya [24]

1mol—44g/mol
0.10mol—x
x=0.10*44
x=4.4 g

8 0

3 years ago

EASY Chemical reactions Balance and classify

Marat540 [252]

Answer:

double replacement

synthesis

double replacement

i think this one is decomposition

synthesis

double replacement

single replacement

double replacement

single replacement .....

hopefully i help

6 0

3 years ago

How many moles is 2. 2 grams of CO2?.

lorasvet [3.4K]

The number of moles of carbon dioxide is 0.05 mol.

A molecule of CO2 contains one carbon atom and two oxygen atoms. One mole of CO2 contains one mole of carbon atoms and two moles of oxygen atoms. The mass of one atomic mole of an element equals the atomic mass in grams, and the molecular mass of an element or compound equals the sum of the atomic masses of each type of its constituent atoms.

Therefore, the mass of one mole of a molecule of an element or compound equals its molecular weight in grams. The number of grams in moles depends on the substance you have. To calculate it, find the atomic or molecular mass of the substance and multiply it by the number of moles.

Learn more about Carbon dioxide here:-brainly.com/question/25385913

#SPJ4

6 0

2 years ago