Answer:
v = 8.96 m/s
Explanation:
Initial speed of the ball, u = 10 m/s
It caught 1 meter above its initial position.
Acceleration due to gravity,
We need to find the final speed of the ball when it is caught. Let is equal to v. To find the value of v, use third equation of motion as :
v = 8.96 m/s
So, the speed of the ball when it is caught is 8.96 m/s. Hence, this is the required solution.
If air were a good conductor of heat" then soup will not stay hot for longer because this time convection+conduction will both help to transfer heat away from soup. Because conduction is the transfer of heat through a substances as a result of neighbouring vibrating particles, The particles in air are far apart.
Snell's law is generally true only when:
1) the beam of light is monochromatic (of one single wavelength, as for example laser beams)
2) the media through which the light beam travels must be isotropic (uniform in all directions, as for example glass)
In these conditions:
sin (r) / sin (i) = n₁ / n₂ = λ₂ / <span>λ</span>₁
The distance the lower spring is stretched from its equilibrium length is 45cm because the weight is 3x as much as the reference spring and the spring constant is the same.
<span>2) The force the bottom spring exerts on the mass is its weight (=mg) PLUS 10.8kg x 3.8m/s^2 = 133N </span>
<span>3) The distance the upper spring is extended from its unstretched length when not accelerated is 15cm </span>
<span>4) Rank the distances the springs are extended from their unstretched lengths: </span>
<span>c) x1 < x2 < x3 </span>
<span>5) The distance the MIDDLE spring is extended from its unstretched length when not accelerated is 45cm </span>
<span>6) Finally, the elevator is moving downward with a velocity of v = -3.4 m/s and also accelerating downward at an acceleration of a = -2.1 m/s2. </span>
<span>a)speeding up </span>
<span>because the v and a are in the same direction</span>
Answer:
The strength of the electric field is 29922.34 N/C
Explanation:
Given;
distance of the electric field, d = 5.2 cm = 0.052 m
charge of the small plastic bead, q = -9 nC = - 9 x 10⁻⁹ C
The strength of the electric field is calculated as;
where;
E is the electric field strength
k is coulomb's constant = 8.99 x 10⁹ Nm²/C²
Therefore, the strength of the electric field is 29922.34 N/C