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MA_775_DIABLO [31]
3 years ago
11

P= f/a solve it for f

Chemistry
1 answer:
Bess [88]3 years ago
7 0

Answer:

Force = Pressure × Area

Explanation:

Easy, just invert the equation. Transpose the force variable over to the left of the equals sign, and transpose the pressure variable back to the right side.

You might be interested in
What is sodium fusion ​
spayn [35]

Answer:

The halogens, nitrogen and sulphur are covalently bonded to the organic compounds. In order to detect them, the elements need to be converted into their ionic forms. This is done by fusing the organic compound with sodium metal. ... The extract is called sodium fusion extract or Lassaigne's extract.

8 0
3 years ago
Given that the nucleophilic substitution reaction used 5.0 mL of t-pentyl alcohol and 12.0 mL of conc. hydrochloric acid to prod
Vladimir [108]

Answer:

4.90 g

Explanation:

Given that:

volume of t-pentyl alcohol = 5 mL

the standard density of t-pentyl alcohol = 0.805 g/mL

Recall that:

density = mass(in wt) /volume

mass = density × volume

mass = 0.805 g/mL × 5 mL

mass = 4.03 g

Volume of HCl used = 12 mL

The reaction for this equation is shown in the image attached below.

From the reaction,

88.15 g of t-pentyl alcohol reacts with concentrated HCl to yield 106.59 g pf t-pentyl chloride.

4.03 g of t-pentyl alcohol forms,

= \dfrac{106.59 \ g \times 4.03 \ g}{88.15 \ g} of t-pentyl chloride.

Therefore,

Theoretical yield of t-pentyl chloride = 4.90 g

8 0
3 years ago
What is the final temperature of the solution formed when 1.52 g of NaOH is added to 35.5 g of water at 20.1 °C in a calorimeter
Inessa [10]

Answer : The final temperature of the solution in the calorimeter is, 31.0^oC

Explanation :

First we have to calculate the heat produced.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy change = -44.5 kJ/mol

q = heat released = ?

m = mass of NaOH = 1.52 g

Molar mass of NaOH = 40 g/mol

\text{Moles of }NaOH=\frac{\text{Mass of }NaOH}{\text{Molar mass of }NaOH}=\frac{1.52g}{40g/mole}=0.038mole

Now put all the given values in the above formula, we get:

44.5kJ/mol=\frac{q}{0.038mol}

q=1.691kJ

Now we have to calculate the final temperature of solution in the calorimeter.

q=m\times c\times (T_2-T_1)

where,

q = heat produced = 1.691 kJ = 1691 J

m = mass of solution = 1.52 + 35.5 = 37.02 g

c = specific heat capacity of water = 4.18J/g^oC

T_1 = initial temperature = 20.1^oC

T_2 = final temperature = ?

Now put all the given values in the above formula, we get:

1691J=37.02g\times 4.18J/g^oC\times (T_2-20.1)

T_2=31.0^oC

Thus, the final temperature of the solution in the calorimeter is, 31.0^oC

4 0
3 years ago
What is the partial pressure of radon if the total pressure is 780 torr and the
Brilliant_brown [7]

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure  = 780torr

Partial pressure of water vapor  = 1.0atm

Unknown:

Partial pressure of radon  = ?

Solution:

A sound knowledge of Dalton's law of partial pressure will help solve this problem.

The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

Mathematically;

           P_{t}   =   P_{1}  + P_{2}   +   P_{n}

Since the total pressure is 780torr, convert this to atm;

                       760torr = 1 atm

                       780torr  = \frac{780}{760} atm  = 1.03atm

     For this problem;

Total pressure  = Partial pressure of radon + Partial pressure of water vapor

            1.03 = Partial pressure of radon + 1.0

  Partial pressure of radon  = 1.03 - 1.00  = 0.03atm

6 0
4 years ago
Estimate the molar mass of a gas that effuses at 1.80 times the effusion rate of carbon dioxide. answer in units of g/mol.
Effectus [21]
From Grahams Law the rates of effusion of two gases are inversely proportional to the square roots of their molar masses at the same temperature and pressure.
Therefore; R1/R2 = √mm2/√mm1
The molecular mass of Carbon dioxide is 44 g
Hence;  1.8 = √(44/x
             3.24 = 44/x
                x = 44/3.24
                   = 13.58 
Therefore, the molar mass of the other gas is 13.58 g/mol
           
3 0
3 years ago
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