Answer:
710,33 g NO2
Explanation:
2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
(800 g octane) / (114.2293 g C8H18/mol x (25/2)) = 87.54 mol O2 used to combust the octane
= 15.44 mol O2 used to form NO2
O2 + 2NO → 2NO2
(15.44 mol O2) x (2/2) x (46.0056 g NO2/mol) = 710,33 g NO2
The question is incomplete. The complete question is:
A certain molecular compound M has a solubility in acetone of 0.737g/mL at 10.°C .Calculate the mass of M that's dissolved in 9.0 L of a saturated solution of M in acetone at this temperature.
Be sure your answer has the correct unit symbol and number of significant digits.
Answer: 6633 g of M is dissolved in 9.0 L of saturated solution in hexane at this temperature.
Explanation:
Given : 0.737g of solute is present in 1ml of solution
i.e 1ml of solution contains = 0.737 g of solute
Thus 9L or 9000ml of solution contains=
Thus 6633 g of M is dissolved in 9.0 L of saturated solution in hexane at this temperature.