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ser-zykov [4K]
4 years ago
9

What is the net force on a 50-newton weight hanging on a string tied to the ceiling?

Physics
1 answer:
Lady bird [3.3K]4 years ago
4 0
The net force on the hanging object is zero. If it were not zero, then the object would be accelerating in some direction.
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Aman tosses a jart upward with a velocity of 14.1 m/s a 60° angle
crimeas [40]

Answer:

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Explanation:

8 0
4 years ago
What is the distance from axis about which a uniform, balsa-wood sphere will have the same moment of inertia as does a thin-wall
andrey2020 [161]

Answer:

D_{s} ≈ 2.1 R

Explanation:

The moment of inertia of the bodies can be calculated by the equation

     I = ∫ r² dm

For bodies with symmetry this tabulated, the moment of inertia of the center of mass

Sphere               Is_{cm} = 2/5 M R²

Spherical shell   Ic_{cm} = 2/3 M R²

The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass

    I = I_{cm} + M D²

Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation

Let's start with the spherical shell, axis is along a diameter

     D = 2R

    Ic = Ic_{cm} + M D²

    Ic = 2/3 MR² + M (2R)²

    Ic = M R² (2/3 + 4)

    Ic = 14/3 M R²

The sphere

    Is =Is_{cm} + M [D_{s}²

    Is = Ic

    2/5 MR² + M D_{s}² = 14/3 MR²

    D_{s}² = R² (14/3 - 2/5)

    D_{s} = √ (R² (64/15)

    D_{s} = 2,066 R

3 0
4 years ago
Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i
garik1379 [7]

Answer

given,

wavelength (λ) = 650 nm

angle = 5°

using bragg's law

sin \theta = \dfrac{n \lambda}{d}

d= \dfrac{n \lambda}{sin \theta}

d= \dfrac{1 \times 650 \times 10^{-9}\ m}{sin5^0}

d = 7.46 x 10⁻⁴ cm

number of slits per centimeter

  = \dfrac{1}{d}\\\Rightarrow \dfrac{1}{7.46\times 10^{-4}}\\\Rightarrow 1340 split per centimeter.

b) wavelength of two rays  650 nm and 420 nm

 d = \dfrac{1}{5000}

     d =  2 x 10⁻6 m

    we now,

sin \theta = \dfrac{n \lambda}{d}

for 650 nm

sin \theta = \dfrac{2\times 650\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.65)

θ = 40.54°

for 450 nm

sin \theta = \dfrac{2\times 450\times 10^{-9}}{2\times 10^{-6}}

\theta =sin^{-1}(0.45)

θ = 24.83°

now, difference

|θ_{650} -θ_{420}| =40.54°-24.83°

|θ_{650} -θ_{420}| =19.71°

8 0
4 years ago
What is your weighted grade, if you have a 100% on homework and a 88% on tests. {homework is worth 40% of grade and tests are wo
Sphinxa [80]
You would have a 92.8, or a 93.
8 0
3 years ago
a girl skateboards with a kinetic energy of 2543.2 J. if the girl and the skateboard have a total mass of 110 kg, what is her sp
zhuklara [117]
     Using the definition of kinetic energy, we have:

E_{c}= \frac{mv^2}{2}  \\ 2543.2*2=110v^2 \\ \boxed {v=6.8m/s}
6 0
3 years ago
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