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4 years ago

What is the net force on a 50-newton weight hanging on a string tied to the ceiling?

1 answer:

4 0

The net force on the hanging object is zero. If it were not zero, then the object would be accelerating in some direction.

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Aman tosses a jart upward with a velocity of 14.1 m/s a 60° angle

crimeas [40]

Answer:

hold on let me check my answer

Explanation:

8 0

4 years ago

What is the distance from axis about which a uniform, balsa-wood sphere will have the same moment of inertia as does a thin-wall

andrey2020 [161]

Answer:

$D_{s}$ ≈ 2.1 R

Explanation:

The moment of inertia of the bodies can be calculated by the equation

I = ∫ r² dm

For bodies with symmetry this tabulated, the moment of inertia of the center of mass

Sphere $Is_{cm}$ = 2/5 M R²

Spherical shell $Ic_{cm}$ = 2/3 M R²

The parallel axes theorem allows us to calculate the moment of inertia with respect to different axes, without knowing the moment of inertia of the center of mass

I = $I_{cm}$ + M D²

Where M is the mass of the body and D is the distance from the center of mass to the axis of rotation

Let's start with the spherical shell, axis is along a diameter

D = 2R

Ic = $Ic_{cm}$ + M D²

Ic = 2/3 MR² + M (2R)²

Ic = M R² (2/3 + 4)

Ic = 14/3 M R²

The sphere

Is = $Is_{cm}$ + M [ $D_{s}$ ²

Is = Ic

2/5 MR² + M $D_{s}$ ² = 14/3 MR²

$D_{s}$ ² = R² (14/3 - 2/5)

$D_{s}$ = √ (R² (64/15)

$D_{s}$ = 2,066 R

3 0

4 years ago

Light of wavelength 650 nm is normally incident on the rear of a grating. The first bright fringe (other than the central one) i

garik1379 [7]

Answer

given,

wavelength (λ) = 650 nm

angle = 5°

using bragg's law

$sin \theta = \dfrac{n \lambda}{d}$

$d= \dfrac{n \lambda}{sin \theta}$

$d= \dfrac{1 \times 650 \times 10^{-9}\ m}{sin5^0}$

d = 7.46 x 10⁻⁴ cm

number of slits per centimeter

= $\dfrac{1}{d}\\\Rightarrow \dfrac{1}{7.46\times 10^{-4}}\\\Rightarrow 1340 split per centimeter.$

b) wavelength of two rays 650 nm and 420 nm

$d = \dfrac{1}{5000}$

d = 2 x 10⁻6 m

we now,

$sin \theta = \dfrac{n \lambda}{d}$

for 650 nm

$sin \theta = \dfrac{2\times 650\times 10^{-9}}{2\times 10^{-6}}$

$\theta =sin^{-1}(0.65)$

θ = 40.54°

for 450 nm

$sin \theta = \dfrac{2\times 450\times 10^{-9}}{2\times 10^{-6}}$

$\theta =sin^{-1}(0.45)$

θ = 24.83°

now, difference

|θ_{650} -θ_{420}| =40.54°-24.83°

|θ_{650} -θ_{420}| =19.71°

8 0

4 years ago

What is your weighted grade, if you have a 100% on homework and a 88% on tests. {homework is worth 40% of grade and tests are wo

Sphinxa [80]

You would have a 92.8, or a 93.

8 0

3 years ago

a girl skateboards with a kinetic energy of 2543.2 J. if the girl and the skateboard have a total mass of 110 kg, what is her sp

zhuklara [117]

Using the definition of kinetic energy, we have:

$E_{c}= \frac{mv^2}{2} \\ 2543.2*2=110v^2 \\ \boxed {v=6.8m/s}$

6 0

3 years ago