They are both part of the reactivity series. check out the reactivity series and u should be able to do it. it’s basically displacement
637,980 Joules is needed to raise the temperature of 2.50 kg of this oil from 23 ∘C to 191 ∘C.
<h3>What is specific heat?</h3>
The heat in calories required to raise the temperature of one gram of a substance one degree Celsius.
Q = cmΔT
where
Q = heat energy needed for that material to get desired temperature change (in Joules)
M = mass (in grams) so you have to convert from kilograms.
c = specific heat constant for the material being heated
ΔT = change in temperature
Q = (1.75)(2.17 x 1000)(191 - 23)
Q = (1.75)(2170)(168)
Q = 637,980 Joules
Hence, 637,980 Joules is needed to raise the temperature of 2.50 kg of this oil from 23 ∘C to 191 ∘C.
Learn more about the specific heat capacity here:
brainly.com/question/9560546
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Answer:
17.27 atm
Explanation:
Use the ideal gas law or PV = nRT
We are solving for pressure here so lets isolate for P before we plug in values:
So first to get n or the number of moles we need to convert the grams of N2O to moles of N2O. We can do this by multiplying by the inverse of the molar mass like so:
Our grams of N2O would cancel and give us 11.813 mol of N2O
Now all thats left is to plug in and solve with the correct value for R which in this case for all of our units to cancel is 0.08206
P = 17.27 atm
(I would double check the calculator work if it is for correctness just be sure)
Answer: 1.00×10^26=1000×10^23
1000×10^23/6.022×10^23=166.05×10^23 moles of water.
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Explanation:
C is the best Awnser to choses