Answer:
The answer to your question is: 0.028 kg of NO2
Explanation:
Data
3.7 x 10²⁰ molecules of NO2 in kg
MW of NO2 = 14 + (16 x 2) = 14 + 32 = 46 kg
1 mol of NO2 --------------------- 6.023 x 10 ²³ molecules
x --------------------- 3.7 x 10²⁰ molecules
x = 3.7 x 10²⁰ x 1 / 6.023 x 10 ²³
x = 0.00061 mol
1 mol of NO2 --------------------- 46 kg of NO2
0.00061 mol ------------------ x
x = 0.00061 x 46/1
x = 0.028 kg of NO2
5) through space
2) refraction
3) bent straw in water
4) aluminum
1) i think it’s A
good luck! :)
Try to untie the knot from the balloon let some air out and tie if back....
The question is incomplete, here is the complete question:
A chemistry student needs 75 g of thiophene foran experiment. He has available 0.50 kg of a 29.3% w/w solution of thiophene in carbon tetrachloride.
Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
<u>Answer:</u> The mass of solution the student should use is 255.97 grams
<u>Explanation:</u>
We are given:
Mass of thiophene needed = 75 gram
29.3 % w/w thiophene solution
This means that 29.3 grams of thiophene is present in 100 grams of solution
Applying unitary method:
If 29.3 grams of thiophene is present in 100 grams of solution
So, 75 grams of thiophene will be present in = 
Given amount of solution = 0.50 kg = 500 grams (Conversion factor: 1 kg = 1000 g)
Hence, the mass of solution the student should use is 255.97 grams