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Arturiano [62]
3 years ago
13

Formula for finding speed using binding energy and mass​

Chemistry
2 answers:
makkiz [27]3 years ago
8 0

Answer:

Energy equivalent to mass defect is termed as binding energy. A nucleus is like an inflexible spherical ball moulded by getting together a huge amount of miniature spherical balls in the nucleons form. Something is required to bound the nucleons collected. It is that something which assists as the glue. Every nucleon has to donate some of its mass, to deliver the energy resulting in a mass defect.

Binding Energy is also defined as the energy required to break down a nucleus into its component nucleons.

Binding Energy is expressed in terms of kJ/mole of nuclei or MeV’s/nucleon.

Binding Energy Formula

Binding Energy = mass defect x c2

where c= speed of light in vacuum

c = 2.9979 x 108 m/s.

Vilka [71]3 years ago
5 0

Answer:

The formula for finding speed using binding energy and mass is E=mc2.

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Answer:

The reduced atom is Br.

Explanation:

  • The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
  • The oxidation process is the process in which electrons are lost and produce positively charged ions.
  • The reduction process is the process in which electrons is gained and negatively charge ions are produced.

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<em></em>

Na loses 1 electrons and is oxidized to Na⁺. (Na → Na⁺ + e).

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Answer : 42 grams of oxygen are required.

Explanation :

Step 1 : Write balanced chemical equation.

The combustion reaction of octane with oxygen can be written as,

2 C_{8}H{18} (g)  + 25  O_{2} (g) \rightarrow 16 CO_{2} (g) +18  H_{2}O (g)

Step 2 : Find moles of octane.

The given mass of octane is 12 g

Molar mass of octane is 114.2 g/mol

The moles of octane are calculated as,

moles =\frac{grams}{MolarMass}  =\frac{12g}{114.2g/mol}  = 0.105 mol

We have 0.105 mol octane.

Step 3: Use mole ratio from balanced equation to find moles of O₂

The mole ratio of octane and O₂ is 2 : 25. Let us use this as a conversion factor.

0.105 mol C_{8}H_{18} \times\frac{25mol O_{2}}{2molC_{8}H_{18}}  = 1.31 mol

We have 1.31 mol O₂.

Step 4 : Convert moles of O₂ to grams.

The molar mass of O₂ is 32 g/mol.

The grams of O₂ can be calculated as,

1.31 mol O_{2} \times\frac{32g}{mol}  = 42 grams

42 grams of oxygen are required.

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