Answer:
Between 5 & 10 MPa in Table B.1.4
Explanation:
150F = 65°C
State 1:
T = 65°C , x = 0.0; Table B.1.1: v = 0,001020 m^3
/kg
Process: T = constant = 65°C
State 2:
T, v = 0.99 x v
f (65°C) = 0.99 x 0,001020 = 0.0010098 m^3
/kg
Between 5 & 10 MPa in Table B.1.4
Answer: (a) 36.18mm
(b) 23.52
Explanation: see attachment
Answer:
9500 kJ; 9000 Btu
Explanation:
Data:
m = 100 lb
T₁ = 25 °C
T₂ = 75 °C
Calculations:
1. Energy in kilojoules
ΔT = 75 °C - 25 °C = 50 °C = 50 K

2. Energy in British thermal units

Answer:
Work = 51,33 kJ
Explanation:
According to the ideal gas equation, the initial volume is calculated as follows:

Then the work for an isobaric process can be calculated using the following expression:

And considering that,

The work can be calculated as follows:
