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natulia [17]
3 years ago
15

Complex poles and zeros. Sketch the asymptotes of the Bode plot magnitude and phase for each of the listed open-loop transfer fu

nctions, and approximate the transition at the second-order break point, based on the value of the damping ratio. After completing the hand sketches, verify your result using Matlab.
L(s)= 1/s(s^2+ 3s+ 10)
Engineering
1 answer:
Sergio [31]3 years ago
7 0
The answer in image

Don't forget put heart ♥️

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Which principle of the software engineering code of ethics has gilbert violated?.
Yuki888 [10]

Answer:

Judgement

Explanation:

Gilbert is required by the Judgement Principle to "disclose those conflicts of interest that cannot reasonably be avoided or escaped." Since Gilbert professionally believes that the software meets specifications, secures documents, and satisfies user requirements, it is not clear if he violated any principle. However, he could have informed his client of his interest in the software and also presented other software packages of different companies from which the client could make its independent choice.

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Consider the simplicity of these two DOE examples. Next, consider the assertion that DOE isn’t put into practice as often or dee
Bingel [31]

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Do Re Mi

Explanation:

I have no clue sorry

5 0
3 years ago
Underground water is to be pumped by a 78% efficient 5- kW submerged pump to a pool whose free surface is 30 m above the undergr
maksim [4K]

Answer:

a) The maximum flowrate of the pump is approximately 13,305.22 cm³/s

b) The pressure difference across the pump is approximately 293.118 kPa

Explanation:

The efficiency of the pump = 78%

The power of the pump = 5 -kW

The height of the pool above the underground water, h = 30 m

The diameter of the pipe on the intake side = 7 cm

The diameter of the pipe on the discharge side = 5 cm

a) The maximum flowrate of the pump is given as follows;

P = \dfrac{Q \cdot \rho \cdot g\cdot h}{\eta_t}

Where;

P = The power of the pump

Q = The flowrate of the pump

ρ = The density of the fluid = 997 kg/m³

h = The head of the pump = 30 m

g = The acceleration due to gravity ≈ 9.8 m/s²

\eta_t = The efficiency of the pump = 78%

\therefore Q_{max} = \dfrac{P \cdot \eta_t}{\rho \cdot g\cdot h}

Q_{max} = 5,000 × 0.78/(997 × 9.8 × 30) ≈ 0.0133 m³/s

The maximum flowrate of the pump Q_{max} ≈ 0.013305 m³/s = 13,305.22 cm³/s

b) The pressure difference across the pump, ΔP = ρ·g·h

∴ ΔP = 997 kg/m³ × 9.8 m/s² × 30 m = 293.118 kPa

The pressure difference across the pump, ΔP ≈ 293.118 kPa

6 0
3 years ago
Compare and contrast an electric vehicle with one powered by a fuel cell.
zmey [24]

Answer:

both technologies offer a cleaner alternative to internal combustion engines, and both use electric motors powered by electrochemical device.

3 0
3 years ago
The customer you were waiting on is nodding while listening to you and gesturing when he speaks what type of language does this
KATRIN_1 [288]
The answer might be Sign language?
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3 years ago
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