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lys-0071 [83]
3 years ago
14

Can ya pls answer dis rq!

Physics
1 answer:
lana66690 [7]3 years ago
5 0

Answer:

For vegetarians beans

Explanation:

Because it's plant protein and very proteinious

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What is the refractive index of air if light travels through it at 3.0 108 m/s?
olchik [2.2K]

Answer:

n = c/v = (3.00 x 108 m/s)/(2.76 x 108 m/s) = 1.09. This does not equal any of the indices of refraction listed in the table.

4 0
2 years ago
The motor in a refrigerator has a power output of 294 W. If the freezing compartment is at 271 K and the outside air is at 310 K
dusya [7]

Answer:

Maximum amount of heat = 10002151.38J

Explanation:

Workdone by motor in 86.1 minutes I given by:

W = power × time

W= 294 × 86.1×60

W= 1439424 Joules

W= 1.4 ×10^6Joules

The amount of heat extracted is given by:

/QL /= K/W/ = TL/W/ /(TH - TL)

Where TL= freezing compartment temperature

TH = Outside air temperature

/QL /= 271 × 1439424 / (310 - 271)

/QL/ = 390083904/39

/QL/ = 10002151.38 Joules

5 0
3 years ago
Read 2 more answers
Change the speed 0.200 cm/s to units kilometers per year
klasskru [66]
The Speed In Kilometers per year is 63.072.
5 0
3 years ago
What effect does increasing mass have on the amount of friction generated
LekaFEV [45]
The greater the mass, the greater the fiction generated
4 0
3 years ago
You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th
PolarNik [594]

<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

Hence, the Young's modulus for the wire is 6.378\times 10^{10}N/m^2

3 0
3 years ago
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