When gasoline burns in the engine, it is oxidised and energy is liberated.
Here the chemical energy of gasoline is converted into mechanical energy to move the vehicle.
<h3><u>Answer;</u></h3>
A.75°C
<h3><u>Explanation</u>;</h3>
Let the change in temp of cold water be x degrees,
while that of hot water be 100 - x degrees.
Heat exchange = mcΔt
Ice
Δt = x
m = 0.50 kg
c = 4.18 kJ/kg*°C
Hot water
Δt = 100 - x
m = 1.5 kg
c = 4.18
But;
Heat lost = heat gained
0.50 * c * x = 1.5 * c * (100 - x)
0.50 *x = 1.5*(100 - x)
0.5x = 150 - 1.5x
0.5x + 1.5x = 150 - 1.5x + 1.5x
2x = 150
x = <u>75° C</u>
Hence; the equilbrium temperature will be 75° C
The answer is B.It decreases the change of the momentum of the person
Answer:
1. The elephant has more kinetic energy at this speed and mass. It has 4,500 J more KE.
2. The elephant would have to go at a speed of 2.5 m/s to reach the same KE as the cheetah.
Explanation:
You would use the formula KE=1/2mv^2.
This formula would be filled in and completed twice, once for the elephant and once for the cheetah.
Cheetah:
KE = 1/2 (40) (25) ^2
KE = 12,500 J
Elephant:
KE = 1/2 (4,000) (2) ^2
KE = 8,000 J
This shows that the cheetah has more KE.
Then you would subtract the elephants amount of J from the cheetahs to find the difference.
Difference = 12,500 J - 8,000 J
Difference = 4,500 J
I hoped this helped with the first part :)
For the second part:
To find the speed the elephant would have to run you would fill in and complete the equation once more with different distance results.
KE = 1/2 (4,000) (2.5) ^2
KE= 12,500 J
