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3 years ago

What happens when you mix water and baking soda

Physics

2 answers:

lord [1]3 years ago

5 0

Nothing much. It doesn’t explode. Lol

AnnZ [28]3 years ago

4 0

Answer:

it explodes

Explanation:

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Which is less likely to be reliable source of information,the webpage of a university or the webpage of a scientist who is tryin

Nikolay [14]

The scientist because he is biased and a university isn't. The scientist will say good things about the invention to sell more of it. Hope this helps! ;)

6 0

3 years ago

Read 2 more answers

Which graph represents a function with direct variation? A coordinate plane with a line passing through (negative 4, 0) and (0,

fgiga [73]

Answer:

Answer:

A line passing through the points (-1,-4),(0,0) and (1,4)

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form y/x=ky/x=k or y=kxy=kx

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Verify each case

Part 1) A line passing through the points (-4,0) and (0,-2)

This line not represent a direct variation, because the line not passes through the origin.

Part 2) A line passing through the points (-5,4) and (0,3)

This line not represent a direct variation, because the line not passes through the origin.

Part 3) A line passing through the points (-4,-6) and (0,3)

This line not represent a direct variation, because the line not passes through the origin.

Part 4) A line passing through the points (-1,-4),(0,0) and (1,4)

The line passes through the origin

Find out the value of k

k=y/xk=y/x

For the point (-1,-4)

substitute

k=-4/-1=4k=−4/−1=4

For the point (1,4)

substitute

k=4/1=4k=4/1=4

The linear equation is y=4xy=4x

This line represent a direct variation

7 0

3 years ago

A car is traveling at a velocity of 22 m/s when the driver puts on the brakes

Brums [2.3K]

The car’s velocity at the end of this distance is 18.17 m/s.

Given the following data:

Initial velocity, U = 22 m/s

Deceleration, d = 1.4 $m/s^2$

Distance, S = 110 meters

To find the car’s velocity at the end of this distance, we would use the third equation of motion;

Mathematically, the third equation of motion is calculated by using the formula;

$V^2 = U^2 + 2dS$

Substituting the values into the formula, we have;

$V^2 = 22 + 2(1.4)(110)\\\\V^2 = 22 + 308\\\\V^2 = 330\\\\V^2 = \sqrt{330}$

Final velocity, V = 18.17 m/s

Therefore, the car’s velocity at the end of this distance is 18.17 m/s.