The amount in grams of Al₂O₃ produced is approximately 6.80 g.
Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:
AL + O₂ → Al₂O₃
Let's balance it
4AL + 3O₂ → 2Al₂O₃
4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,
Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,
Atomic mass of AL = 27 g
Molar mass of Al₂O₃ = 101.96 g/mol
4(27 g) of AL gives 2(101.96 g) of Al₂O₃
3.6 g of AL will give ?
cross multiply
mass of Al₂O₃ produced = 3.6 × 203.92 / 108 = 734.112 / 108 = 6.797
mass of Al₂O₃ produced = 6.80 g.
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The answer is B
Explanation:
Can you mark brainliest I correct
Answer:
(a) Polarity of phase: 1. Stationary phase is polar
b) Eluent strength of solvent: 1. Increases as solvent becomes more polar
c) Nature of solutes.1. Polar
d) Nature of solute interaction:2. More soluble in mobile phase as the polarity of the mobile phase decreases
e) Polarity of phases: 1. Stationary phase is polar
f) Eluent strength of solvent: 1. Increases as solvent becomes more polar.
g) Nature of solutes: 1. Polar
h) Nature of solute interaction: 2. More soluble in mobile phase as the polarity of the mobile
Explanation:
According to this formula:
Q = M*C*ΔT
when we have M ( the mass of water) = 200 g
and C ( specific heat capacity ) of water = 4.18 J/gC
ΔT (the difference in temperature) = Tf - Ti
= 100 - 24
= 76°C
So by substitution:
Q = 200 g * 4.18 J/gC * 76 °C
= 63536 J
∴ the amount of heat which be added and absorbed to raise the temp from 24°C to 100°C is = 63536 J
Answer:
See explanation
Explanation:
What I have written in the image attached is called a nuclear equation. It differs from a chemical reaction equation in the sense that it involves transformations that occur in the nucleus of atoms.
The nuclear equation must be balanced. This means that the mass and charge on both sides of the reaction equation must be the same.
On the left hand side the U-235 interacts with a neutron. The total mass on the left hand side is 236 while the total charge is 92. If we sum up the masses and charges of Ba and Kr, we also get a total of 236 mass units and a charge of 92.
Hence the other nucleus is barium-141
