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PSYCHO15rus [73]

2 years ago

6

When the following reaction reached equilibrium at 325 K , the equilibrium constant was found to be 172. When a sample was taken

of the equilibrium concentration, it was found contain 0.2 M NO2. What was the equilibrium concentration of N2O4? 2NO2(g) <--> N2O4(g)

1 answer:

miss Akunina [59]2 years ago

6 0

Answer: 6.88M

Explanation:

K= [N204]/[NO2]^2

[NO2]= 0.2M

K=172

[N204]=K * [N02]^2

172 *0.2^2

=6.88M

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3 years ago

2KCIO3 -- 2KCL+3o2 is a balanced equation

Veronika [31]

Answer:

a)<em> Balanced equation:</em>

An equation is called balanced if there are same number and same type of atom on both sides of the equation.

b)<em>Reason:</em>

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3 years ago

A 1.00 L buffer solution is 0.112 M in acetic acid and 0.112 M in sodium acetate. Acetic acid has a pKa of 4.74. What is the pH

topjm [15]

Answer:

ΔpH = 1.25

Explanation:

Using Henderson-Hasselbalch formula:

pH = pka + log [CH₃COONa] / [CH₃COOH]

pH = 4.74 + log [0.112] / [0.112]

<em>pH = 4.74</em>

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CH₃COONa + HCl → CH₃COOH + NaCl

<em>Producing acetic acid, </em>CH₃COOH.

If 0.1mol of HCl reacts the final moles of CH₃COONa are:

0.112mol - 0,1 mol = 0.012mol

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0.112mol + 0,1 mol = 0.212mol

Using Henderson-Hasselbalch formula:

pH = pka + log [CH₃COONa] / [CH₃COOH]

pH = 4.74 + log [0.012] / [0.212]

<em>pH = 3.49</em>

<em></em>

Change in pH, ΔpH = 4.74 - 3.49 =<em> 1.25</em>

I hope it helps!

6 0

2 years ago