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3 years ago

6

3) All numbers that are divisible by both 3 and 5 are also divisible by 10. Which of the following numbers can be used to show t

hat the statement above is FALSE? (A) 20 (B) 25 (C) 30 (D) 40 (E) 45

1 answer:

zlopas [31]3 years ago

8 0

Answer:

answer E

Explanation:

cuz its 45 is divisible by 3 and 5 but not 10

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Describe the image of an object that is 38 cm from a concave mirror that has a focal length of 10 cm.

harina [27]

Let's start by using the mirror equation:
$\frac{1}{f}= \frac{1}{d}+ \frac{1}{q}$
where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:
$\frac{1}{q}= \frac{1}{f}- \frac{1}{d} = \frac{1}{10 cm}- \frac{1}{38 cm}$
from which we find q=13.6 cm.

The fact that q is positive means that the image is real, so it is on the same side of the object, with respect to the mirror.

Then we can also find the size of the image with respect to the original object. The magnification is given by
$M=- \frac{q}{d} =- \frac{13.6}{38}=-0.36$
The negative sign means that the image is inverted, and the size of the image is 0.36 times the size of the object.

4 0

3 years ago

answers Collision derivation problem. If the car has a mass of 0.2 kg, the ratio of height to width of the ramp is 12/75, the in

Natasha2012 [34]

Answer:

4.8967m

Explanation:

Given the following data;

M = 0.2kg

∆p = 0.58kgm/s

S(i) = 2.25m

Ratio h/w = 12/75

Firstly, we use conservation of momentum to find the velocity

Therefore, ∆p = MV

0.58kgm/s = 0.2V

V = 0.58/2

V = 2.9m/s

Then, we can use the conservation of energy to solve for maximum height the car can go

E(i) = E(f)

1/2mV² = mgh

Mass cancels out

1/2V² = gh

h = 1/2V²/g = V²/2g

h = (2.9)²/2(9.8)

h = 8.41/19.6 = 0.429m

Since we have gotten the heigh, the next thing is to solve for actual slant of the ramp and initial displacement using similar triangles.

h/w = 0.429/x

X = 0.429×75/12

X = 2.6815

Therefore, by Pythagoreans rule

S(ramp) = √2.68125²+0.429²

S(ramp) = 2.64671

Finally, S(t) = S(ramp) + S(i)

= 2.64671+2.25

= 4.8967m

3 0

3 years ago

A concave mirror has a focal length of 0.20 m. If an object produces a virtual image

Contact [7]

As per the given question,
Focal length of the concave mirror(f)=0.25m
position of virtual image form the mirror (v)=0.04m
let the position of the object from the concave mirror (u)=?
u=3.44cm

5 0

4 years ago

Suppose you wanted to improve a moving.coil microphone so that it was more sensitive (e, so that it outputs a stronger induced e

Ne4ueva [31]

Answer:

d. All of the above .

Explanation:

The sensitivity of microphone will be more if even feeble sound can create greater vibration in diaphragm . Naturally it is possible if diaphragm is light and can move easily . The movement it it is controlled by current in the coil which makes it electromagnet . All factors that increase the strength of magnet like increasing the no of turns , or a strong magnet will increase the sensitivity.

6 0

4 years ago

A force is acting on a 3-kg object during 5 seconds. If the object initially has a speed of 1.5m/s and after applying the force

uranmaximum [27]

Answer:

1.5 N

Explanation:

You've left us to guess what the question is. I will Assume it is what's the force?

Givens

m = 3 kg

vi = 1.5 m/s

vf = 4 m/s

t = 5 seconds

Formula

F = m * (vf - vi)/t

Solution

F = 3 * (4 - 1.5) / 5

F = 1.5 N

3 0

3 years ago