As the radius increases the circumference increases.
Answer:
(a) 1.2 rad/s
(b) 1.8 rad
Explanation:
Applying,
(a) α = (ω-ω')/t................ Equation 1
Where α = angular acceleration, ω = final angular velocity, ω' = initial angular velocity, t = time.
From the question,
Given: α = 0.40 rad/s², t = 3 seconds, ω' = 0 rad/s (from rest)
Substitute these values into equation 1
0.40 = (ω-0)/3
ω = 0.4×3
ω = 1.2 rad/s
(b) Using,
∅ = ω't+αt²/2.................. Equation 2
Where ∅ = angle turned.
Substitutting the values above into equation 2
∅ = (0×3)+(0.4×3²)/2
∅ = 1.8 rad.
The direction of the magnetic force is to the right.
<h3>What is the magnetic field?</h3>
The magnetic field is the region in space where the influence of the magnet is felt. The magnetic force is always in the direction of the magnetic field.
We can see from the image, that the direction of the magnetic force is to the right.
Learn more about magnetic field:brainly.com/question/14848188
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A thermogram is a representation of infrared electromagnetic waves better known as heat waves. So the correct answer is infrared electromagnetic waves or infrared waves.
Explanation:
The thermogram is associated with infrared camera creates a picture by changing effulgent heat into a symbol which will be displayed on a monitor (and later printed). The infrared energy emitted from the associated object is directly proportional to its temperature. Thus it can be used for temperatures that are accurately measured by the infrared camera.
Answer:
0.0665 days
Explanation:
We are given;
The mean distance from the Earth's center to the moon;a1 = 385000 km
The mean distance from the Earth's center to the space craft;a2 = 6965 km
Formula for kepplers third law is;
T² = 4π²a³/GM
However, the proportion of both distances would be;
(T1)²/(T2)² = (a1)³/(a2)³
Where;
T1 is the period of orbit of the moon around the earth. T1 has a standard value of 27.322 days
T2 is the period of the space craft orbit.
Making T2 the subject, we have;
T2 = √((T1)²×(a2)³)/(a1)³)
Thus, plugging in the relevant values;
T2 = √(27.322² × 6965³)/(385000)³
T2 = 0.0665 days