If the emf produced in a wire is 0.88 volts and the wire moves perpendicular to a magnetic field of strength 0.075 newtons/amper
2 answers:
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Answer:
Explanation:
To solve this equation we will have to consider that the bubble is filled with an Ideal Gas and as such we can use the Ideal Gas Law
Where
= Pressure
= Volume
= Moles
= Ideal Gas Constant
= Temperature
Now since we know that the value for the temperature and moles is constant we can simply use Boyles Law for the two states
Let us look at the two states
State 1 (at top)
Pressure =
Volume =
State 2 (at bottom)
Pressure =
Where
= Density of liquid (1000 kg/m³)
= Acceleration due to gravity (9.8 m/s²)
= Height of liquid (0.200 m)
Pressure =
Volume =
Inputting these values into the Boyles Law
Answer:
e.)At twice the distance, the strength of the field is E/4.
Explanation:
The strength of the electric field at a certain distance from a point charge is given by:
where
k is the Coulomb's constant
Q is the charge
r is the distance from the point charge
In this problem, the distance from the point charge is doubled:
r' = 2r
So the new electric field strength is
so, at twice the distance the strength of the field is E/4.