Answer:
V₂ = 750 mL
Explanation:
Given data:
Initial pressure = 3 atm
Initial volume = 2000 mL
Final pressure = 8 atm
Final volume = ?
Solution:
The given problem will be solved through the Boyle's law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
3 atm × 2000 mL = 8 atm × V₂
V₂ =6000 atm. mL / 8atm
V₂ = 750 mL
According to Charle's Law,
V/T = constant
where
V = volume
T = absolute temperature.
The law holds when the pressure of an ideal gas is held constant while temperature changes.
V₁ = 2.33 L, initial volume
T₁ = 30°C = 30+273 K = 303 K, initial temperature
T₂ = 300°C = 300+273 K = 573 K, final temperature
The final volume, V₂, is given by
V₂/T₂ = V₁/T₁
V₂ = (573 K)*(2.33/303 L/K)
= 4.406 L
Answer: 4.41 L
Answer: When a pendulum is at the bottom of its swing, it has kinetic energy.
Explanation: At the bottom of a swing, the greatest speed is achieved. Speed/Velocity equals Kinetic Energy, as potential energy is when speed is at its lowest.
According to Le Chatelier's Principle, to increase the rate of the forward reaction we add more of the reactants to encourage more collisions and production of more products. If it is endothermic, more heat should be added. If it is endothermic, more heat should be released from the system.
Answer:
1.67g H2CO3 are produced
Explanation:
Based on the reaction:
2NaHCO3 → Na2CO3 + H2CO3
<em>2 moles of NaHCO3 produce 1 mole of Na2CO3 and 1 mole of H2CO3</em>
To solve this question we need to find the moles of Na2CO3 = Moles of H2CO3. With their moles we can find the mass of H2CO3 as follows:
<em>Moles Na2CO3 -Molar mass: 105.99g/mol-</em>
2.86g Na2CO3 * (1mol/105.99g) = 0.02698 moles Na2CO3 = Moles H2CO3
<em>Mass H2CO3 -Molar mass: 62.03g/mol-</em>
0.02698 moles * (62.03g/mol) =
<h3>1.67g H2CO3 are produced</h3>
