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Pavlova-9 [17]
3 years ago
13

........................

Physics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

14°F = 263.15 K

31°F = 272.594 K

71°F = 294.817 K

35°F = 274.817 K

Explanation:

Use the formula 273.15 + ((°F–32)•5)/9

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A moving freight car runs into an identical car at rest on the track. The cars couple together. Compared to the velocity of the
Leno4ka [110]

Answer:

one half as large , initial velocity is two times larger

Explanation:

Momentum is conserved.

p₁ + p₂ = p₁' + p₂'

m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'

m₁ = m₂ =m , v₂= 0

v₁' =v₂'

mv₁ = 2mv₁'

v₁ = 2v₁'

8 0
3 years ago
A crew team rows a boat at a rate of 20 km/h in still water. Beginning at time = 0 minutes, the team rows for 30 minutes up a ri
umka21 [38]
Since they are rowing against the current, their velocity realtive to the groud is 20-1.5 = 18.5km/h
So the distance travelled is 18.5km/h*0.5h = 9.25km
Going back with the current their ground realative velocity is 20+1.5 = 21.5km/h so the time it takes them to return 9.25 km is 9.25km/(21.5km/h) = 0.43h ~= 26 min
7 0
3 years ago
Jaipal measures a circuit at 1.2 A and 24 . Using Ohm’s law, what can he calculate for the circuit? current (C) current (I) volt
jenyasd209 [6]

Answer: voltage (V)

Explanation:

Hi, in the answer the letter A (1.2 A) stands for Ampere, and the symbol next to the number 24 must be Ω 8 (Ohms)

So, applying Ohm's law:

Voltage (V) =current (I) x resistance (R)

V = I x R

Replacing with the values given;

V = 1.2 A x 24Ω

In conclusion, we can calculate the value of Voltage for the circuit.

Feel free to ask for more if needed or if you did not understand something.

4 0
3 years ago
Read 2 more answers
¿Cuál será la potencia de una bombilla conectada a una red de energía eléctrica de 440V, si la corriente que circula por el circ
goblinko [34]

Answer:

La potencia de la bombilla es de 1056 W.

Explanation:

La potencia de la bombilla se puede calcular usando la siguiente ecuación:

P = I*V

En donde:

P: es la potencia

I: es la corriente = 2,4 A

V: es la diferencia de potencial = 440 V

Entonces, la potencia es:

P = I*V = 2,4 A*440 V = 1056 W

Por lo tanto, la potencia de la bombilla es de 1056 W.

Espero que te sea de utilidad!

3 0
3 years ago
5 facts about mars plz
damaskus [11]
Mars is 141,600,000 miles from the Sun
The mass is 639E21 kg 
One day length is 24 hours and 40 minutes
The radius is 2,106 miles
And has 2 moons, Phobos and Deimos 
5 0
3 years ago
Read 2 more answers
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