Answer:
When a teen driver drives with a lot of his peers as passengers they may lead to distraction which may later end up in accident as the driver was distracted
velocity of object just before hitting the ground = 10 m/s
10 m/sExplanation:
here's the solution : -
=》mechanical energy is always constant, when the object is at the top of the building , the object has potential energy but no kinetic energy,
so, at the top of the building the mechanical energy = potential energy = 100 J
but at when it is dropped from the building, the whole potential energy get converted into kinetic energy, just before reaching the bottom .
so, mechanical energy in the object just before hitting the ground = kinetic energy
( potential energy = 0 )
So, kinetic energy = 100 J
now, we know
=》
( since, mass = 2 kg )
=》
=》
=》
so, velocity of object just before hitting the ground = 10 m/s
Answer:
u = 104.68 m/s
Explanation:
given,
horizontal distance = 150 m
elevation of 12.4 m
angle = 8.6°
horizontal motion = x = u cos θ. t .............(1)
vertical motion =
................(2)
from equation(1) and (2)
..........{3}
u = 104.68 m/s
The initial speed of the ball is u = 104.68 m/s
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Answer:
a = (v² − v₀²) / (2 (x − x₀))
Explanation:
v² = v₀² + 2a(x − x₀)
Subtract v₀² from both sides.
v² − v₀² = 2a(x − x₀)
Divide both sides by 2 (x − x₀).
(v² − v₀²) / (2 (x − x₀)) = a