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PolarNik [594]
3 years ago
5

Người ta ném một hòn bi theo phương ngang với vận tốc ban đầu là 15m/s và nó rơi xướng đất sau 4s. Bỏqua sức cản của không khí v

à lấy g=10 m/s2. Hỏi hòn bi được ném từđộcao nào và tầm xa của nó là bao nhiêu?
Physics
1 answer:
Juliette [100K]3 years ago
5 0

Answer:

h = 80m L = 60m

Explanation:

Độ cao Ng ta ném hòn bi là

t=\sqrt{\frac{2h}{9}} => 4^2 = \frac{2h}{10}

h= 80m

Tầm bay xa:

L= Vo . t = 15.4 = 60m

Chúc học tốt nghen

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