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notka56 [123]
2 years ago
10

An alternating voltage of 25.0 V is connected across the primary coil of a transformer.

Physics
1 answer:
uranmaximum [27]2 years ago
7 0

Answer:

A

Explanation:

Wattage = E * I

E = 25

I = 5

Wattage = 25 * 5

Wattage = 125

The secondary, in an ideal transformer has the same wattage.

125 = 50 * I           Divide by 50

125/50 = I

I = 2.5

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3 years ago
Lee skated 36 miles in 3 hours. What was the speed at which Lee
Zanzabum

Answer:

12mph

Explanation:

36/3=mph

8 0
3 years ago
Can someone explain to me #4.
nalin [4]
A) We balance the masses: 4(1.00728) vs 4.0015 + 2(0.00055)4.02912 vs. 4.0026This shows a "reduced mass" of 4.02912 - 4.0026 = 0.02652 amu. This is also equivalent to 0.02652/6.02E23 = 4.41E-26 g = 4.41E-29 kg.
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4 0
2 years ago
An object with velocity 141 ft/s has a kinetic energy of 1558.71 ft∙lbf, on a planet whose gravity is 31.5 ft/s2. What is its
Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m  = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \  \times \ \ \ \ 1   \ lbf\ }

m  = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71  \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm

Therefore, the mass of the object is 5.045 lbm.

6 0
2 years ago
A book is to be produced with pages of thickness 0.125mm.If the book is to be exactly 1cm thick what is the maximum number of pa
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Answer:

1cm=10mm

10cm/0.125mm

80pages

5 0
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