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3 years ago

An alternating voltage of 25.0 V is connected across the primary coil of a transformer.

Physics

1 answer:

uranmaximum [27]3 years ago

7 0

Answer:

Explanation:

Wattage = E * I

E = 25

I = 5

Wattage = 25 * 5

Wattage = 125

The secondary, in an ideal transformer has the same wattage.

125 = 50 * I Divide by 50

125/50 = I

I = 2.5

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An asteroid orbiting the Sun has a mass of 4.00×1016 kg. At a particular instant, it experiences a gravitational force of 3.14×1

Ksivusya [100]

<h2>The asteroid is 4.11 x 10¹¹ m far from Sun</h2>

Explanation:

We have gravitational force

$F=\frac{GMm}{r^2}$

Where G = 6.67 x 10⁻¹¹ N m²/kg²

M = Mass of body 1

M = Mass of body 2

r = Distance between them

Here we have

M = Mass of Sun = 1.99×10³⁰ kg

m = Mass of asteroid = 4.00×10¹⁶ kg

F = 3.14×10¹³ N

Substituting

$F=\frac{GMm}{r^2}\\\\3.14\times 10^{13}=\frac{6.67\times 10^{-11}\times 1.99\times 10^{30}\times 4\times 10^{16}}{r^2}\\\\r=4.11\times 10^{11}m$

The asteroid is 4.11 x 10¹¹ m far from Sun

3 0

3 years ago

What is one result of warming up your body’s muscles before exercising?

Anna11 [10]

Slightly raising your body temperature while increase oxygen and blood circulation throughout your body

7 0

3 years ago

Which of the following is the best thermal insulator?

Vera_Pavlovna [14]

B. Aluminum is possibly correct

4 0

3 years ago

Two protons are 9.261 fm apart. (1 fm= 1 femtometer = 1 x 10^-15 m.) What is the ratio of the electric force to the gravitationa

Strike441 [17]

Answer:

$1.24\times 10^{36}$

Explanation:

$q$ = magnitude of charge on each proton = 1.6 x 10⁻¹⁹ C

$m$ = mass of each proton = 1.67 x 10⁻²⁷ kg

r = distance between the two protons = 1 x 10⁻¹⁵ m

Electric force between the two protons is given as

$F_{e} = \frac{kq^{2}}{r^{2}}$

$F_{e} = \frac{(9\times 10^{9})(1.6\times 10^{-19})^{2}}{(1\times 10^{-15})^{2}}$

$F_{e} = 230.4$ N

Gravitational force between the two protons is given as

$F_{g} = \frac{Gm^{2}}{r^{2}}$

$F_{g} = \frac{(6.67\times 10^{-11})(1.67\times 10^{-27})^{2}}{(1\times 10^{-15})^{2}}$

$F_{g} = 1.86\times 10^{-34}$ N

Ratio is given as

$Ratio =\frac{F_{e}}{F_{g}}$

$Ratio =\frac{230.4}{1.86\times 10^{-34}}$

$Ratio = 1.24\times 10^{36}$

3 0

3 years ago

Read 2 more answers

If the total momentum for a system is the same before and after the collision, we say that momentum is conserved. If momentum we

andrew-mc [135]

Answer:

Ratio = 1:1

Explanation:

$P_{i}$ = initial momentum of the system

$P_{f}$ = final momentum of the system

For the momentum to be conserved , final total momentum must be equal to initial total momentum, so we have

$P_{f} = P_{i}$

Dividing both side by $P_{i}$ , we get

$\frac{P_{f}}{P_{i}} = \frac{P_{i}}{P_{i}} \\\frac{P_{f}}{P_{i}} = 1\\$

hence

Ratio = 1

5 0

3 years ago