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Inessa [10]
1 year ago
6

Which of the following objects have kinetic energy?

Physics
1 answer:
Montano1993 [528]1 year ago
4 0
I think the Answer is A (An elephant walking 1.5 m/s along the ground), and B (A jet flying across the sky 4,000 m above the ground.
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Brittle- would break when struck with force *<br> A-Metal<br> B-Nonmetal<br> C-Metalloid
bazaltina [42]

-B because metal hardly breaks but non metal items such as glass or plastic does!

4 0
2 years ago
Read 2 more answers
Gravity on Jupiter is 25 m/s/s, what is the weight of a 12 kg object on Jupiter?
stiv31 [10]

Answer:

300 Newtons

Explanation:

Weight is the force of attraction between two bodies, one usually larger (like a planet), and one smaller (like a person). Force can be calculated using the formula: Force = mass × acceleration.

The mass here is 12kg, the acceleration, which in this case, is the acceleration due to gravity is 25m/s/s, by plugging in our values, we have

Force = 12 × 25 = 300 Newtons or 300 N for short.

3 0
2 years ago
While trying out for the position of pitcher on your high school baseball team, you throw a fastball at 87.6 mi/h toward home pl
JulijaS [17]
The ball drops about 1 m.

8 0
2 years ago
If a 1 kg book has 46 Joules of gravitational potential energy how high is the shelf it is on?
Mashcka [7]

Answer:

4.7m

Explanation:

Given parameters:

Mass of the book  = 1kg

Gravitational potential energy  = 46J

Unknown:

Height of the shelf  = ?

Solution:

The potential energy is due to the position of a body above the ground.

        Gravitational potential energy  = mgh

m is the mass,

g is the acceleration due gravity  = 9.8m/s²

h is the height which is unknown

                       46  = 1 x 9.8 x h

                       h  = 4.7m

4 0
2 years ago
In a fast-pitch softball game the pitcher is impressive to watch, as she delivers a pitch by rapidly whirling her arm around so
svetlana [45]

Answer:

(a). The magnitude of the total acceleration of the ball is 239.97 m/s².

(b). The angle of the total acceleration relative to the radial direction is 11.0°

Explanation:

Given that,

Radius of the circle = 0.681 m

Angular acceleration = 67.7 rad/s²

Angular speed =18.6 rad/s

We need to calculate the centripetal acceleration of the ball

Using formula of centripetal acceleration

a_{c}=\omega^2\times r

Put the value into the formula

a_{c}=(18.6)^2\times0.681

a_{c}=235.5\ m/s^2

We need to calculate the tangential acceleration of the ball

Using formula of tangential acceleration

a_{t}=r\alpha

Put the value into the formula

a_{t}=0.681\times67.7

a_{t}=46.104\ m/s^2

(a). We need to calculate the magnitude of the total acceleration of the ball

Using formula of total acceleration

a=\sqrt{a_{c}^2+a_{t}^2}

Put the value into the formula

a=\sqrt{(235.5)^2+(46.104)^2}

a=239.97\ m/s^2

(b). We need to calculate the angle of the total acceleration relative to the radial direction

Using formula of the direction

\theat=\tan^{-1}(\dfrac{a_{t}}{a_{c}})

Put the value into the formula

\theta=\tan^{-1}(\dfrac{46.104}{235.5})

\theta=11.0^{\circ}

Hence, (a). The magnitude of the total acceleration of the ball is 239.97 m/s².

(b). The angle of the total acceleration relative to the radial direction is 11.0°

5 0
3 years ago
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