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andrezito [222]
3 years ago
8

Si un auto se mueve en rapidez constante de 25,0m/s a lo largo de 2500 m en línea recta, ¿cuál es la magnitud de la fuerza resul

tante?
Physics
1 answer:
Nataly_w [17]3 years ago
3 0

Answer:

F= 0

Explanation:

This exercise we use Newton's second law,

            F = m a

in this case as the speed is constant the acceleration is zero therefore the force is zero.

Change we can solve it using Newton's first law, which states that every vehicle remains still or with constant speed if there is no extensive outside acting on it

We see that with any of the two forms the sum of the applied forces is zero

                     ∑ F = 0

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Ok I have no clue for this one I’m not sure what to make out of this one please help
MatroZZZ [7]

Helium, Neon, and Xenon are all part of the same column on the Periodic Table. Such a column is referred to as a Group, because they have the same number of valence electrons in their outermost shell. Hope this helps!

5 0
3 years ago
A physical change occurs when a material changes shape or size but the composition of the material does not change. True or Fals
Elden [556K]
It is true that a physical change occurs when a material changes shape or size, but the composition of the material does not change. The correct answer is True. 
6 0
2 years ago
Calculate the work done by an applied force of 76.0 N on a crate for the following. (Include the sign of the value in your answe
telo118 [61]

Answer:

a) 400.4Joules

b) 262.69Joules

Explanation:

Work is said to be done if the force applied to an object cause the object to move through a distance

Workdone = Force × Distance

Given

Force = 76N

Distance= 5.2m

Work done = 77 × 5.2

Work done = 400.4Joules

b) If the force is exerted at an angle of 41°

Work done = Fdsin theta

Work done = 77(5.2)sin41

Work done = 400.4sin41

Work done = 262.69Joules

6 0
3 years ago
When operated on a household 110.0 V line, typical hair dryers draw about 1650 W of power. The current can be modeled as a long,
Andre45 [30]

Explanation:

Given that,

Voltage of household line, V = 110 V

Power of the hairdryer, P = 1650 W

During use, the current is about 1.95 cm from the user's hand.

(a) Power is given by :

P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1650\ W}{110\ V}\\\\I=15\ A

(b) Again the power is given by :

P=\dfrac{V^2}{R}

R is resistance of the dryer

R=\dfrac{V^2}{P}\\\\R=\dfrac{(110)^2}{1650}\\\\R=7.34\ \Omega

(c) The magnetic field produced by the dryer at the user's hand is given by :

B=\dfrac{\mu_o I}{2\pi r}\\\\B=\dfrac{4\pi \times 10^{-7}\times 15}{2\pi \times 1.95\times 10^{-2}}\\\\B=1.53\times 10^{-4}\ T

Hence, this is the required solution.

4 0
3 years ago
A wheel with moment of inertia 25 kg. m2 and angular velocity 10 rad/s begins to speed up, with angular acceleration 15 rad/sec2
Pani-rosa [81]

Answer:

(A) Angular speed 40 rad/sec

Rotation = 50 rad

(b) 37812.5 J

Explanation:

We have given moment of inertia of the wheel I=25kgm^2

Initial angular velocity of the wheel \omega _0=10rad/sec

Angular acceleration \alpha =15rad/sec^2

(a) We know that \omega =\omega _0+\alpha t

We have given t = 2 sec

So \omega =10+15\times  2=40rad/sec

Now \Theta =\omega _0t+\frac{1}{2}\alpha t^2=10\times 2+\frac{1}{2}\times 15\times 2^2=50rad

(b) After 3 sec \omega =10+15\times 3=55rad/sec

We know that kinetic energy is given by Ke=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 25\times 55^2=37812.5J

7 0
3 years ago
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