First find the oxidation states of the various atoms:
<span>in Cr2O2 2- Cr @ +1; In NH3 N @ +3; in CrO3 Cr @ +3, N2 N @ 0 </span>
<span>Note that N gained electrons, ie, was reduced; Cr was oxidized </span>
<span>Now there is a problem, because B has NH4+ which the problem did not, and is not balanced, showing e- in/out </span>
<span>B.NH4+ → N2 </span>
<span>Which of the following is an oxidation half-reaction? </span>
<span>A.Sn 2+ →Sn 4+ + 2e- </span>
<span>Sn lost electrons so it got oxidized</span>
Answer:
Percentage lithium by mass in Lithium carbonate sample = 19.0%
Explanation:
Atomic mass of lithium = 7.0 g; atomic mass of Chlorine = 35.5 g; atomic mass of carbon = 12.0 g; atomic mass of oxygen = 16.0 g
Molar mass of lithium chloride, LiCl = 7 + 35.5 = 42.5 g
Percentage by mass of lithium in LiCl = (7/42.5) * 100% = 16.4 % aproximately 16%
Molar mass of lithium carbonate, Li₂CO₃ = 7 * 2 + 12 + 16 * 3 =74.0 g
Percentage by mass of lithium in Li₂CO₃ = (14/74) * 100% = 18.9 % approximately 19%
Mass of Lithium carbonate sample = 2 * 42.5 = 85.0 g
mass of lithium in 85.0 g Li₂CO₃ = 19% * 85.0 g = 16.15 g
Percentage by mass of lithium in 85.0 g Li₂CO₃ = (16.15/85.0) * 100 % = 19.0%
Percentage lithium by mass in Lithium carbonate sample = 19.0%
According to Newton's Second law of motion, t<span>he force acting on an object is equal to the mass of that object times its acceleration. The acceleration of the vehicle is caused by the force that is applied and the mass it posses. Hope this answers the question.</span>
Answer:
0.006 mol of CaCl2 are present
Explanation:
Use dimensional analysis for this:
60.0 mL CaCl2/1 * 1 L/1000 mL * 0.10 mol/1 L = 0.006 mol
If you were to write this as fractions out on paper, you'll see that all of the units will cancel out and you'll be left with moles of CaCl2.
**REMEMBER** that molarity (M) is talking about how many moles of that substance is present in one Liter of solvent.
Hope this helps :)
Answer:
raspunde in explicatie
Explanation:
În această întrebare, trebuie să scriem formula și să numim compusul.
A. 1 atom de azot și 3 atom de hidrogen Aceasta este NH3 și numele este amoniac
b. 2 atomi de hidrogen, 1 atom de carbon și 3 atomi de oxigen Adică H2CO3 Trioxocarbonat (iv)
C. 1 atom de carbon și 2 atomi de oxigen CO2 Oxid de carbon (iv)
d. 1 atom de calciu și 1 carbonat de grupă Aceasta este CaCO3 Adică trioxocarbonatul de calciu iv
e. Pb (II) și un carbonat Aceasta este PbCO3 Acesta este carbonatul de plumb (ii)
f. Grupa de cobalt 2 și fosfați
adică
Co3(PO4)2
Cobalt (ii) tetraoxofosfat (v)
g.Arsenic și radical sulfurat Adică As2S3 Trisulfida de arsen