Answer:
![h_2-h_1=6\times 10^{-3}\frac{KJ}{Kg}](https://tex.z-dn.net/?f=h_2-h_1%3D6%5Ctimes%2010%5E%7B-3%7D%5Cfrac%7BKJ%7D%7BKg%7D)
Explanation:
Now from first law for open system
![h_1+\dfrac{V_1^2}{2}+Q=h_2+\dfrac{V_2^2}{2}+w](https://tex.z-dn.net/?f=h_1%2B%5Cdfrac%7BV_1%5E2%7D%7B2%7D%2BQ%3Dh_2%2B%5Cdfrac%7BV_2%5E2%7D%7B2%7D%2Bw)
Here given Q=0 ,w=0
So ![h_1+\dfrac{V_1^2}{2}=h_2+\dfrac{V_2^2}{2}](https://tex.z-dn.net/?f=h_1%2B%5Cdfrac%7BV_1%5E2%7D%7B2%7D%3Dh_2%2B%5Cdfrac%7BV_2%5E2%7D%7B2%7D)
![V_1=4 m/s,V_2=2 m/s](https://tex.z-dn.net/?f=V_1%3D4%20m%2Fs%2CV_2%3D2%20m%2Fs)
![h_1+\dfrac{4^2}{2000}=h_2+\dfrac{2^2}{2000}](https://tex.z-dn.net/?f=h_1%2B%5Cdfrac%7B4%5E2%7D%7B2000%7D%3Dh_2%2B%5Cdfrac%7B2%5E2%7D%7B2000%7D)
![h_2-h_1=6\times 10^{-3}](https://tex.z-dn.net/?f=h_2-h_1%3D6%5Ctimes%2010%5E%7B-3%7D)
So increase in specific enthalpy
![h_2-h_1=6\times 10^{-3}\frac{KJ}{Kg}](https://tex.z-dn.net/?f=h_2-h_1%3D6%5Ctimes%2010%5E%7B-3%7D%5Cfrac%7BKJ%7D%7BKg%7D)
Explanation:
We assume the T flip-flop changes state on the rising edge of the clock input.
The first stage is connected to the clock. The second stage clock is connected to the inverse of the Q output of the first stage, so that when the first stage Q makes a 1 to 0 transition, the second stage changes state.
Answer:
Most environmental consultants are employed by consultancy firms
Answer: A Biomass
Explanation: it is organic matter