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Firdavs [7]
3 years ago
11

A football player carrying the ball runs straight ahead at the line of scrimmage and directly into a wall of defensive linemen.

The ball carrier has an initial speed of 7.68 m/s and is stopped in a time interval of 0.202 s. Find the magnitude and direction of his average acceleration.
Physics
1 answer:
lyudmila [28]3 years ago
4 0
For this problem, we use the derived equations for rectilinear motion at constant acceleration. The equation is:

a = (v -v₀)/t
where
v and v₀ is the final and initial velocities, respectively
t is time
a is acceleration

Since it eventually comes to a stop, v=0. Substituting the values,
a = (0 - 7.68 m/s)/0.202 s
a = -38.02 m/s²

Hence, the magnitude of the acceleration is -38.02 m/s². The direction is still aiming along the straight line, but the negative sign signifies that the the ball is decelerating.
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