Explanation:
NA2SO3
Combination of these three elements forms following compounds.
And the compound that's going to be formed,depends on the ratio of available oxygen and sulphur.
Depends on the ratio of sulfur to oxygen...
sodium sulfate, Na2SO4
sodium sulfite, Na2SO3
sodium thiosulfate, Na2S2O3
ionic bond is present in between SO3 -2 and Na+2
structure of SO3 -2 [take - sign as delta - which here indicates,partial formal charge of oxygen] (image below)
Here,The oxygen is more electronegative.So,2 oxygen atoms drag one Electron from sulphur atom,leaving behind the formal charge of -1 on two oxygen atoms.
The third oxygen forms covalent bond by sharing 2 electrons. (Actually this ion has resonance structure)
This sulphite ion combines with two sodium ions to form two ionic bonds.This happens when sodium, being an alkali metal dontes it's valence electron to oxygen.
SO2
In Sulphur dioxide, Sulphur is bonded to 2 oxygen atoms. Oxygen is more electronegative than Sulphur and thus, shows a fixed valency of 2. As a result each oxygen forms two bonds with the Sulphur atom making its valency 4.
NAHSO4
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Questions & Answers
CBSE
Chemistry
Grade 11
Oxidation State or Oxidation Number
Question
Answers
Related Questions
The oxidation state of sulphur in NaHSO4 ?
A) 0
B) + 2
C) −2
D) + 4
E) + 6
Answer
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72.9K+ Views
Hint: The oxidation state is defined as the charge on the atom. The sum of the oxidation state of an atom in a molecule is equal to the charge on the molecule. The neutral molecules charge less species. It has zero charges.
Complete Solution :
- The oxidation number of an atom is defined as the charge on an atom that appears on the atom on forming an ionic bond. An atom which has higher electronegativity has a negative oxidation state and more electropositive elements have positive oxidation state.
- We are interested in determining the oxidation state of an atom in a molecule. We know that the net charge on a neutral atom or molecule is always equal to zero. Let’s determine the oxidation state of S in the NaHSO4 .
- The oxidation number of alkali metal that is a sodium atom is equal to +1 . Similarly the hydrogen has an +1 oxidation state. Oxygen is an electronegative element. It has an −2 oxidation state. The oxidation states are as listed below:
Element Oxidation state
Na +1
H +1
O −2
We know that the sum of the oxidation state of an atom in a neutral molecule is equal to zero. Then we have,
0 = O.S. of Na + O.S. of H + O.S. of S + 4(O.S. of O)
Let’s substitute the values of oxidation state .we have,
0 = 1 + 1 + O.S. of S + 4(−2)⇒O.S. of S= 8−2 = +6
Therefore the oxidation state of sulphur in NaHSO4 is equal to +6 . So, the correct answer is “Option E”.
H2S
Valency of sulphur is 2 in H2S
