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Rainbow [258]
3 years ago
15

If a tube is 2.2 meters in length, how long is the the tube in feet ?​

Chemistry
1 answer:
trapecia [35]3 years ago
3 0

Answer:

7.22 feet long

Explanation:

1 meter = 3.28084 feet

2.2 × 3.28084 = 7.2<u>1</u>785

= 7.22

I hope this is helpful :)

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How many ml of co2 would be produced at 745 torr and 28°C
Marizza181 [45]

Answer:

Se aplica la leyes d ellos gases ideales para esto se convierten las unidades de Presión en atmósferas y Temperatura a Kelvin y si no se tiene el volumen el volumen equivale a 22.4Litros

Explanation:

3 0
3 years ago
A student decomposed 3.67g of copper (ii) hydroxide into copper (ii) oxide. how many ml of 3m h2so4 is need to react with all th
vredina [299]
In the presence of heat, copper (II) hydroxide decomposes in to copper (II) oxide. 
Cu(OH)₂ (s) ----> CuO (s) + H₂O (l)
upon decomposition, water is removed from Cu(OH)₂
the amount of Cu(OH)₂ decomposed - 3.67 g
number of moles of Cu(OH)₂  - 3.67 g / 97.5 g/mol = 0.038 mol
stoichiometry of Cu(OH)₂ to CuO is 1:1
therefore number of CuO moles formed are - 0.038 mol
CuO reacts with sulfuric acid to form CuSO₄ 
CuO + H₂SO₄ ---> CuSO₄ + H₂O
stoichiometry of CuO to H₂SO₄ is 1:1
therefore number of H₂SO₄ moles that should react is 0.038 mol
the molarity of H₂SO₄ is 3M
this means that in 1000 ml - 3 mol of H₂SO₄ present 
so if 3 mol are present in 1000 ml 
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6 0
3 years ago
He diagram below represents part of the oxygen cycle.
salantis [7]

Answer:

The answer is C

Explanation:

7 0
3 years ago
Calculate the boiling point of a solution of 500.0 g of ethylene glycol (c2h6o2) dissolved in 500.0 g of water. kf = 1.86°c/m a
Bingel [31]

Answer:The boiling point of the solution is 108° C.

Explanation:

Boiling point of pure water=T=100^oC

Boiling point of water after addition of 500 g of ethylene glycol=T_f

Mass of water = 500g = 0.5 kg (1000 g = 1 kg)

\Delta T_f=K_b\times \frac{\text{Mass of ethlyene glycol}}{\text{Molar mass of ethylene glycol}}

\Delta T_f=0.512^oC/m\times \frac{500 g}{62.07 g/mol\times 0.5 kg}

\Delta T_f=8.24 ^oC

\Delta T_f=T_f-T

8.24^oC=T_f-100^oC

T_f=108.24^oC

The boiling point of the solution is 108° C.

7 0
3 years ago
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