You describe it as a chemical change. When matter reacts to other matter it is called a chemical change.
3.1613994181344593 moles of MgC12 (3.16)
I’m not sure but I think the answer is B
B when the amount of available plankton is greatly reduced. This would increase fighting among fish for food.
Answer:
0.0042 M is the molarity of tartaric acid in this sample of wine.
Explanation:
To calculate the concentration of acid, we use the equation given by neutralization reaction:
![n_1M_1V_1=n_2M_2V_2](https://tex.z-dn.net/?f=n_1M_1V_1%3Dn_2M_2V_2)
where,
are the n-factor, molarity and volume of acid which is tartaric acid
are the n-factor, molarity and volume of base which is NaOH.
We are given:
![n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL](https://tex.z-dn.net/?f=n_1%3D2%5C%5CM_1%3D%3F%5C%5CV_1%3D10.0%2B40.0%20mL%3D50.0%20mL%5C%5Cn_2%3D1%5C%5CM_2%3D0.051%20M%20M%5C%5CV_2%3D8.20%20mL)
Putting values in above equation, we get:
![2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL](https://tex.z-dn.net/?f=2%5Ctimes%20M_1%5Ctimes%2050.0%20mL%3D1%5Ctimes%200.051%20M%5Ctimes%208.20%20mL)
![M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M](https://tex.z-dn.net/?f=M_1%3D%5Cfrac%7B1%5Ctimes%200.051%20M%5Ctimes%208.20%20mL%7D%7B2%5Ctimes%2050.0%20mL%7D%3D0.0042%20M)
0.0042 M is the molarity of tartaric acid in this sample of wine.