All categories

3 years ago

Why do you seem to "fly forward" when you slam on the brakes of a car? what forces are involved?

1 answer:

8 0

Its because of inertia.
due to inertia u tries to be in the same state of motion, in this case u have a tendency to remain in forward motion as the car suddenly tries to stop, so u move forward.
all the best

You might be interested in

John flies directly east for 20km, then turns to the north and flies for another 10 km before dodging a flock of geese. what’s t

KIM [24]

The distance is 30 km and the displacement is 22.4 km North East

7 0

3 years ago

A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien

n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

$\phi=NBA$

Put the value into the formula

$\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2$

$\phi=7.85\times10^{-7}\ Tm^2$

We need to calculate the induced emf

Using formula of induced emf

$\epsilon=\dfrac{d\phi}{dt}$

Put the value into the formula

$\epsilon=\dfrac{7.85\times10^{-7}}{dt}$

Put the value of emf from ohm's law

$\epsilon =IR$

$IR=\dfrac{7.85\times10^{-7}}{dt}$

$Idt=\dfrac{7.85\times10^{-7}}{R}$

$Idt=\dfrac{7.85\times10^{-7}}{0.50}$

$Idt=0.00000157=1.57\times10^{-6}\ C$

We know that,

$Idt=dq$

$dq=1.57\times10^{-6}\ C$

We need to calculate the voltage across the capacitor

Using formula of charge

$dq=C dV$

$dV=\dfrac{dq}{C}$

Put the value into the formula

$dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}$

$dV=1.57\ V$

Hence, The voltage across the capacitor is 1.57 V.

5 0

3 years ago

A 12 kg bowling ball would require what force to accelerate it down an alley at a rate of 2.5 m/s ^ 2

alisha [4.7K]

Answer:

Explanation:

hiijjjjjjjjjjjjjjj

8 0

3 years ago

A 1.45 kg 1.45 kg falcon catches a 0.415 kg 0.415 kg dove from behind in midair. What is their velocity after impact if the falc

jarptica [38.1K]

Answer: The velocity is 21.5m/s

Explanation:

Let's call:

M1 and V1 as the mass and velocity of the falcon:

M1 = 1.45kg

V1 = 26.5m/s

M2 and V2 as the mass and velocity of the dove:

M2 = 0.415kg

V2 = 4.35m/s

Where both velocities are positive because both animals move in the same direction.

We can think that the interaction between both animals is a perfectly inelastic collision, because afther the interaction they move as one. Then, we have that the final velocity of both animals togheter is:

V = (V1*M1 + V2*M2)/(M1 + M2)

V = (1.45kg*26.5m/s + 0.415kg*4.35m/s)/(1.45kg + 0.415kg) = 21.5m/s

7 0

3 years ago

Suppose an air bubble is trapped in the eudiometer before starting the experiment. After the experiment is finished, the resulti

seraphim [82]

Answer:

Explanation:

The resulting valie would be too large

8 0

3 years ago