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3 years ago

Why do you seem to "fly forward" when you slam on the brakes of a car? what forces are involved?

1 answer:

8 0

Its because of inertia.
due to inertia u tries to be in the same state of motion, in this case u have a tendency to remain in forward motion as the car suddenly tries to stop, so u move forward.
all the best

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How tilted is the axis of the earth's rotation as compared to the plane of the earth's orbit?

Phantasy [73]

C. 23.5 degrees
This tilt in the axis causes the seasons.
Hope this helps.

6 0

3 years ago

Read 2 more answers

Starting from rest, the distance a freely-falling object will fall in 0.50 second is?

FinnZ [79.3K]

Answer:

1.23 m

Explanation:

The vertical distance covered by a free-falling object starting from rest in a time t is

$y=\frac{1}{2}gt^2$

where

g = 9.8 m/s^2 is the acceleration due to gravity

In this problem, we have

t = 0.50 s

So the distance covered is

$y=\frac{1}{2}(9.8 m/s^2)(0.50 s)^2=1.23 m$

8 0

3 years ago

PLEASE HELP!

Harman [31]

Hey user!

your answer is here..

correct option is A. steel

we know that sounds travel faster in solid as compared to gas and liquids. in gas the molecules are very loosely packed and there is lot of space between so it takes more time to pass sound from each other. and in liquid, the molecules are closer as compared to gas hence it will be little faster and in solid, the molecules are very tightly packed so it will be the fastest. and among these options, steel is the only solid so the speed of sound in steel will be the fastest.

and note that the closer the molecules are to each other ( tightly packed ) makes the bond also tighter and less time to pass sound.

cheers!!

8 0

3 years ago

Help me with this please

Elanso [62]

care labels

2. do not dry wash

do not iron

4 0

3 years ago

Read 2 more answers

At the equator, near the surface of the Earth, the magnetic field is approximately 50.0 μT northward, and the electric field is

n200080 [17]

a) $8.93\cdot 10^{-30} N$ , downward

b) $1.76\cdot 10^{-17} N$ , upward

c) $1.20\cdot 10^{-17} N$ , downward

Explanation:

The gravitational force of an object (also known as weight of the object) is the attractive force with which the object is pulled towards the Earth's centre.

For an object near the Earth's surface, the magnitude of the gravitational force is given by the equation

$F=mg$

where

m is the mass of the object

g is the acceleration due to gravity

In this problem, we have:

$m=9.11\cdot 10^{-31} kg$ is the mass of the electron

$g=9.8 m/s^2$ is the acceleration due to gravity

Therefore, the gravitational force on the electron is:

$F=(9.11\cdot 10^{-31})(9.8)=8.93\cdot 10^{-30} N$

And the direction is downward, towards the Earth's centre.

The electric force on a charged particle is the force produced by the presence of an electric field.

In particular, this force is:

- Repulsive (away from the source of the field) if the charge has the same sign of the charge source of the field

- Attractive (towards the source of the field) if the charge has opposite sign to the charge source of the field

The magnitude of the electric force is given by:

$F=qE$

where

q is the charge of the particle

E is the strength of the electric field

In this problem:

$q=1.6\cdot 10^{-19} C$ is the charge of the electron

$E=110 N/C$ is the strength of the electric field

Substituting,

$F=(1.6\cdot 10^{-19})(110)=1.76\cdot 10^{-17} N$

And since the electron has negative charge, the direction of the force is opposite to that of the electric field, so upward.

When a charged particle is moving in a magnetic field, it experiences a force which is perpendicular to both the direction of motion of the charge and to the direction of the magnetic field.

The magnitude of this force is given by (if the charge moves perpendicular to the magnetic field)

$F=qvB$

where

q is the charge

v is the velocity of the particle

B is the strength of the magnetic field

In this problem:

$q=1.6\cdot 10^{-19} C$ is the charge of the electron

$v=1.50\cdot 10^6 m/s$ is the velocity

$B=50.0\mu T = 50.0 \cdot 10^{-6} T$ is the strength of the magnetic field

Substituting,

$F=(1.6\cdot 10^{-19})(1.50\cdot 10^6)(50.0\cdot 10^{-6})=1.20\cdot 10^{-17} N$

And the direction can be determined using the right-hand rule:

- Index finger: direction of velocity (eastward)

- Middle finger: direction of magnetic field (northward)

- Thumb: direction of force (upward) --> however the electron has negative charge, so the direction of the force is reversed --> downward

5 0

3 years ago