Answer:
There are 5 main conditions of the alveoli for proper gaseous exchange to in the lungs.
Explanation
Alveoli is found in the lungs of mammals, birds and reptiles. It is the part of the lungs where gaseous exchange really occurs.
Alveoli has a shape of that of balloon but indeed smaller than the real balloon. It allows the passage of oxygen and carbon dioxide
The five main conditions includes:
- The Alveoli must have large surface to volume ratio which increase the gases that could be exchanged
- The wall must be thin. This can shorten diffusion distance.
- Alveoli must be very moist so that oxygen and carbon dioxide can pass through the solution
- Alveoli must be well supplied with blood
- Alveoli must be permeable
Answer:
5.09 m/s
Explanation:
Use the height to find the time it takes to land:
y = y₀ + v₀ᵧ t + ½ gt²
0 = 8.0 m + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 1.28 s
Now use the horizontal distance to find the initial velocity.
x = x₀ + v₀ₓ t + ½ at²
6.5 m = 0 m + v₀ (1.28 s) + ½ (0 m/s²) (1.28 s)²
v₀ = 5.09 m/s
Kilogram(kg)
It's not the SI unit of mass in the metric system however.
Answer:
net power is + 2.25 D
Explanation:
Given data
distance vision = -0.25 D
near vision = + 2.50 D
to find out
net power
solution
we have given a person lens power for near is - 0.25 diopter and lens power for near power is +2.50 diopter so
net power is sum of both the power vision
so
net power = distance + near power
put both value we get net power
net power = ( -0.25 D) + ( + 2.50 D)
net power = + 2.25 D
so net power is + 2.25 D
Answer:
the coefficient of volume expansion of the glass is 
Explanation:
Given that:
Initial volume of the glass flask = 1000 cm³ = 10⁻³ m³
temperature of the glass flask and mercury= 1.00° C
After heat is applied ; the final temperature = 52.00° C
Temperature change ΔT = 52.00° C - 1.00° C = 51.00° C
Volume of the mercury overflow = 8.50 cm^3 = 8.50 × 10⁻⁶ m³
the coefficient of volume expansion of mercury is 1.80 × 10⁻⁴ / K
The increase in the volume of the mercury = 10⁻³ m³ × 51.00 × 1.80 × 10⁻⁴
The increase in the volume of the mercury = 
Increase in volume of the glass = 10⁻³ × 51.00 × 
Now; the mercury overflow = Increase in volume of the mercury - increase in the volume of the flask
the mercury overflow = 
Thus; the coefficient of volume expansion of the glass is
