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Rom4ik [11]
3 years ago
14

What happens when a lamp plugged into an electrical outlet is turned on?

Physics
2 answers:
anzhelika [568]3 years ago
7 0
<span>B.The form of energy changes, but the total energy remains the same.</span>
MArishka [77]3 years ago
5 0
<span>. The electrical energy is converted into heat and light energy. Matter and energy can neither be created nor destroyed but changes from one form to another 
so correct one is
</span>The form of energy changes, but the total energy remains the same
so its B
hope it helps
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A pendulum with a length of 1.00 m is released from an initial angle of 12.5°. After 1 000 s, its amplitude has been reduced by
Viefleur [7K]

Answer:

A student is conducting a pendulum experiment. Which of the following pieces of safety equipment would be the most vital to conduct this test?

Explanation:nduebidndo eyn h ehj jd

jknsjk Jjkfnjkjnuifvr

7 0
3 years ago
Part 1: Fill in the SI unit for each of the following measurements. 1. Time: 2. Length: 3. Mass: 4. Temperature:
Alik [6]

Answer:

1. Time: Second

2. Length: Meter

3. Mass: Kilogram

4. Temperatur: Kelvin

Explanation:

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3 0
3 years ago
A student pushes on a 5 kg box with a force of 20 N forward. The force of sliding friction
mart [117]

Answer:

Explanation:

F=20N

mu=-10N

F=ma

20-10=10

10=(5)(a)

a=2 m/s^2

4 0
3 years ago
Electromagnetic radiation of 8.12×10¹⁸ Hz frequency is applied on a metal surface and caused electron emission. Determine the wo
klemol [59]

Answer:

The work function ϕ of the metal = 53.4196 x 10⁻¹⁶ J      

Explanation:

When light is incident on a photoelectric material like metal, photoelectrons are emitted from the surface of the metal. This process is called photoelectric effect.

The relationship between the maximum kinetic energy (E_{k}) of the photoelectrons to the frequency of the absorbed photons (f) and the threshold frequency (f₀) of the photoemissive metal surface is:

                                        E_{k} = h(f − f₀)

                                        E_{k} = hf - hf₀

E is the energy of the absorbed photons:  E = hf

ϕ is the work function of the surface:  ϕ = hf₀

                                        E_{k} = E - ϕ

Frequency f = 8.12×10¹⁸ Hz

Maximum kinetic energy E_{k} = 4.16×10⁻¹⁷ J  

Speed of light  c = 3 x 10⁸ m/s

Planck's constant h = 6.63 × 10⁻³⁴ Js                                

                                        E = hf = 6.63 × 10⁻³⁴ x 8.12×10¹⁸

                                        E = 53.8356 x 10⁻¹⁶ J

from E_{k} = E - ϕ ;

                                        ϕ = E - E_{k}

                                        ϕ = 53.8356 x 10⁻¹⁶ - 4.16×10⁻¹⁷

                                        ϕ = 53.4196 x 10⁻¹⁶ J

The work function of the metal ϕ = 53.4196 x 10⁻¹⁶ J      

4 0
3 years ago
A certain parallel-plate capacitor is filled with a dielectric for which κ = 5.0. The area of each plate is 0.027 m2, and the pl
alexdok [17]

Answer:

Energy will be 4.776\times 10^{-5}J  

Explanation:

We have given that dielectric constant k = 5

Area of the plate A=0.027m^2

Distance between the plates d=2mm=2\times 10^{-3}m

Electric field E = 200 kN/C

We know that capacitance is given by C=\frac{K\epsilon _0A}{d}=\frac{5\times 8.85\times 10^{-12}\times 0.027}{2\times 10^{-3}}=0.597\times 10^{-9}F

We know that electric field is given by E=\frac{V}{d}

So V=Ed=200\times 10^3\times 2\times 10^{-3}=400volt

So energy will be E=\frac{1}{2}CV^2=\frac{1}{2}\times 0.597\times 10^{-9}\times 400^2=4.776\times 10^{-5}J

6 0
3 years ago
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