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Reika [66]
3 years ago
15

Please someone derive 3rd equation of motion u- v= 2sa​

Physics
2 answers:
zlopas [31]3 years ago
6 0

We know

\\ \sf\longmapsto a=\dfrac{dv}{dt}

\\ \sf\longmapsto a=\dfrac{dv}{dx}.\dfrac{dx}{dt}

\\ \sf\longmapsto a=v\dfrac{dv}{dx}

\\ \sf\longmapsto adx=vdv

  • Integrate

\\ \sf\longmapsto a{\displaystyle{\int}^x_{x_0}}dx=\displaystyle{\int}_u^v vdv

\\ \sf\longmapsto a(x-x_0)=\dfrac{v^2-u^2}{2}

Here

  • x-x_0=s

\\ \sf\longmapsto v^2-u^2=2as

Kitty [74]3 years ago
3 0

mark me as brainliest ❤️

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Help please ............
Solnce55 [7]

Answer:

47c

Explanation:

5 0
3 years ago
(a) a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerte
Musya8 [376]

The dimension of force, F is ML/T².

<h3>What is force?</h3>

Force is a push o push agent which causes a change in the state of rest or motion of an object.

From a fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerted on the object and inversely proportional to its mass.

Mathematically; acceleration ∝ F/m

F = ma

dimension of Mass = M

dimension of acceleration = L/T²

dimension of force, F = ML/T²

In conclusion, the dimension of force is obtained from the dimensions of mass and acceleration.

Learn more about dimension of force at: brainly.com/question/28243574

#SPJ1

5 0
2 years ago
A baseball is hit into the air with a velocity of 27 m/s. How high does it go?
Marizza181 [45]

Answer:

Explanation:

If a baseball is hit into the air with a velocity of 27 m/s, we want to determine the maximum height of the ball. Using the projecile formula;

Max height H = u²/2g

u is the initial velocity of the body = 27m/s

g is the acceleration due to gravity = 9.81m/s²

H = 27²/2(9.81)

H = 729/19.62

H = 37.16m

Hence the ball went 37.16m high

8 0
3 years ago
A ball rolls 60 centimeters along a sidewalk in 5 seconds what is the speed of the ball.
meriva

Answer:

12 cm/s

Explanation:

Quite simply, you are looking for  cm/s

  so   60 cm / 5s   = 12 cm/s

6 0
2 years ago
Read 2 more answers
A 290 gg bird flying along at 6.2 m/sm/s sees a 9.0 gg insect heading straight toward it with a speed of 34 m/sm/s (as measured
Murrr4er [49]

Answer:

The bird's speed immediately after swallowing is 4.98 m/s.

Explanation:

Given that,

Mass of bird = 290 g

Speed = 6.2 m/s

Mass of sees = 9.0 g

Speed = 34 m/s

We need to calculate the bird's speed immediately after swallowing

Using conservation of momentum

m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{3}

Put the value into the formula

0.290\times6.2+0.009\times(-34)=(0.290+0.009)\times v_{3}

v_{3}=\dfrac{0.290\times6.2-0.009\times34}{(0.290+0.009)}

v_{3}=4.98\ m/s

Hence, The bird's speed immediately after swallowing is 4.98 m/s.

6 0
3 years ago
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