This question is not complete.
The complete question is as follows:
One problem for humans living in outer space is that they are apparently weightless. One way around this problem is to design a space station that spins about its center at a constant rate. This creates “artificial gravity” at the outside rim of the station. (a) If the diameter of the space station is 800 m, how many revolutions per minute are needed for the “artificial gravity” acceleration to be 9.80m/s2?
Explanation:
a. Using the expression;
T = 2π√R/g
where R = radius of the space = diameter/2
R = 800/2 = 400m
g= acceleration due to gravity = 9.8m/s^2
1/T = number of revolutions per second
T = 2π√R/g
T = 2 x 3.14 x √400/9.8
T = 6.28 x 6.39 = 40.13
1/T = 1/40.13 = 0.025 x 60 = 1.5 revolution/minute
Answer:
Iron
Explanation: It is by mass the most common element on Earth, right in front of oxygen, forming much of Earth's outer and inner core.
Answer:
20.4e18 electrons/second ≈ 2e19 electrons/second
Explanation:
Hi!
To solve this problem we are going to use Omh's Law:
V = RI
And the relation ship between the resistance R and conductivity:
R = L/(σA)
*here we are considering a omhic material*
The conductance σ is related to electron mobility and electron density by:
σ = nμ
Replacing all these relations in the omhs law, we get:
V = (LI)/(σA)
We know that both wire are subject to the same electric field, therefore V is the same for both, moreover, since no additional info for the length of the wires is given we are going to consider that L is the same for both. Therefore
This means that:
From the relation of the conductance and electron mobility and density, and the data given to us, we know that:
Also
Therefore:
That is:
Since I_A = 3*10^18 e/s
I_B = 20.4*10^18 e/s
It is a reflecting telescope and a compound microscope. I know this for sure