Answer:
-2.79 m/s²
Explanation:
Given:
v₀ = 20 m/s
v = 11 m/s
Δx = 50 m
Find: a
v² = v₀² + 2aΔx
(11 m/s)² = (20 m/s)² + 2a (50 m)
a = -2.79 m/s²
Round as needed.
Answer:
Force is 14.93N along positive y axis.
Explanation:
We know that force 'F' on a current carrying conductor placed in a magnetic field of intensity B is given by
![\overrightarrow{F}=\overrightarrow{Il}\times \overrightarrow{B}](https://tex.z-dn.net/?f=%5Coverrightarrow%7BF%7D%3D%5Coverrightarrow%7BIl%7D%5Ctimes%20%5Coverrightarrow%7BB%7D)
where L is the length of the conductor
Applying values in the equation we have force F =
![\overrightarrow{F}=6.8\times 6.1\widehat{k}\times 0.36\widehat{i}\\\\\overrightarrow{F}=41.48\widehat{k}\times 0.36\widehat{i}\\\\\therefore \overrightarrow{F}=14.93N\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7BF%7D%3D6.8%5Ctimes%206.1%5Cwidehat%7Bk%7D%5Ctimes%200.36%5Cwidehat%7Bi%7D%5C%5C%5C%5C%5Coverrightarrow%7BF%7D%3D41.48%5Cwidehat%7Bk%7D%5Ctimes%200.36%5Cwidehat%7Bi%7D%5C%5C%5C%5C%5Ctherefore%20%5Coverrightarrow%7BF%7D%3D14.93N%5Cwidehat%7Bj%7D)
Thus force is 14.93N along positive y axis.
Answer:
The work done on the suitcase is, W = 1691 J
Explanation:
Given data,
The force on the suitcase is, F = 89 N
The distance Russell dragged the suitcase, S = 19 m
The work done on the suitcase by Russell is equal to the work done on the suitcase to overcome the friction
The work done on the suitcase by Russell is given by the formula
W = F · S
Substituting the given values,
W = 89 N x 19 m
W = 1691 J
Hence, the work done on the suitcase is, W = 1691 J
Answer:
Strong electrical currents in close proximity to the magnet.
Other magnets in close proximity to the magnet.
Neo magnets will corrode in high humidity environments unless they have a protective coating.
Explanation: Heat radiation