Answer:
88.89 cm
Explanation:
We are given that
Distance between bulb and wall=4 m=
1 m=100 cm
Let h be the height of object
Object distance=-u
Image distance= v
Height of object=2h
Magnification=
Lens formula
1. <span> Fp = Mg*sin24 = 0.407Mg. </span>
<span>Fn = Mg*Cos24 = 0.914Mg. </span>
<span>Fk = u*0.914Mg. </span>
<span>Fp-Fk = M*a. </span>
<span>0.407Mg-u*0.914Mg = M*a.
</span>Divide by Mg:
<span>0.407-0.914u = a/g = 3.1/-9.81, </span>
<span>0.407-.914u = -0.316, uk = 0.791.
</span>
2. <span> M*g = 1200*9.8 = 11,760 N. = Wt. of car. = Normal force(Fn). </span>
<span>Fp = Mg*sin 0 = 0. </span>
<span>Fk = uk*Fn = 0.1323*11,760 = 1556 N. </span>
<span>Fp-Fk = M*a. </span>
<span>0-1556 = 1200a, a = -1.30 m/s^2. </span>
<span>V^2 = Vo^2 + 2a*d. </span>
<span>0 = (20.1)^2 - 19.6d
</span>