Answer:
The answer to your question is V2 = 4.97 l
Explanation:
Data
Volume 1 = V1 = 4.40 L Volume 2 =
Temperature 1 = T1 = 19°C Temperature 2 = T2 = 37°C
Pressure 1 = P1 = 783 mmHg Pressure 2 = 735 mmHg
Process
1.- Convert temperature to °K
T1 = 19 + 273 = 292°K
T2 = 37 + 273 = 310°K
2.- Use the combined gas law to solve this problem
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
-Substitution
V2 = (783 x 4.40 x 310) / (292 x 735)
-Simplification
V2 = 1068012 / 214620
-Result
V2 = 4.97 l
When a large fissile atomic nucleus such as uranium-235 or plutonium-239 absorbs a neutron, it may undergo nuclear fission. The heavy nucleus splits into two or more lighter nuclei, (the fission products), releasing kinetic energy, gamma radiation, and freeneutrons
Answer: 1.80g
Explanation:
Molar Mass of AlCl3 = 27 + (3x35.5)
= 27 + 106.5 = 133.5g/mol
Number of mole of AlCl3 = 0.0135mol
Mass = 0.0135 x 133.5= 1.80g
Density<span> is </span>defined<span> as the ratio between mass and volume or mass per unit volume.
Source is google
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The mass of the sample reported is 3.5465 g option e is correct.
Mass is the quantitative measure of the physical body.
The mass of the empty sample container is given as 12 g.
The mass of empty as well as sample containers is given as 15.5465 g.
Therefore, the mass of the sample will be given as :
Mass of sample = mass of a sample as well as empty containers - a mass of empty sample container
= 15.5465 - 12
= 3.5465 g
Therefore, the mass of the sample reported is 3.5465 g option e is correct.
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brainly.com/question/26150306
# SPJ4
Complete question:
Your question is incomplete, but most probably your full question was, A label on an empty sample container reads 12.00 g. you add in a sample of a compound and the mass of the sample container obtaining 15.5465 g. what should the mass of the sample be reported as?
a) 3.546 g
b) 3.54 g
c) 4 g
d) 4.0 g
e) 3.5465 g
