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IrinaVladis [17]
3 years ago
11

Valora la importancia de los alcoholes dentro de la medicina e industria indagando riesgos MEDICINA​

Chemistry
1 answer:
VikaD [51]3 years ago
5 0

Answer:

diwjjwjdnsjakkakakalalskb

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HELP!!!! A glass flask containing 100 milliliters of water is sealed with a rubber stopper and placed on a burner. After a while
kondor19780726 [428]

Answer: A closed system, because energy can enter or leave the container, but the water molecules cannot

Explanation:

Open system: In this system energy and matter both have access to their surroundings beyond the boundaries of system. .

Closed system :In this type system only energy has an access to its surroundings beyond the boundaries of system but not matter.

Isolated system:In this type system exchange of both energy and matter are restricted to move outside the boundaries of system.

According to question, the system given is a closed system because energy is transferred from the burner to glass flask and from the glass flask to the water (matter). But water molecules are only getting condensed on the inside surface of the flask that is exchange of matter beyond the boundaries of the system is restricted. Hence, closed system ,A closed system, because energy can enter or leave the container, but the water molecules cannot.

7 0
3 years ago
Which of the following is an example of a compound?<br><br> CaCl2<br><br> Na<br><br> Nd<br><br> Cu
madam [21]
CaCl2

All of the other choices are elements
5 0
3 years ago
On which side of an equation are the reactants found?
koban [17]
The reactants are found on the Left of the arrow :)
6 0
3 years ago
The chemical formula for lithium phosphide is li3p
Oxana [17]
Sodium phosphide is the inorganic compound with the formula Na3P.
4 0
4 years ago
A compound is composed of only C, H, and O. The combustion of a .519-g sample of the compound yields 1.24 g of CO_2 and .255 g o
Kay [80]

Answer:

Empirical formula is C₃H₃O.

Explanation:

Given data:

Mass of compound = 0.519 g

Mass of CO₂ = 1.24 g

Mass of H₂O = 0.255 g

Empirical formula = ?

Solution:

%age of C,H,O

C = 1.24 g/0.519 × 12/44 ×100 = 65.5%

H = 0.255 g/0.519 × 2.016/18 ×100 =  5.6%

O = 100 - (65.5+5.6)

O = 28.9%

Number of gram atoms of H = 5.6 / 1.01 = 5.5

Number of gram atoms of O =  28.9 / 16 = 1.81

Number of gram atoms of C = 65.5 / 12 = 5.5

Atomic ratio:

            C                      :        H              :         O

          5.5/1.81              :       5.5/1.81     :       1.81/1.81

            3                      :        3              :        1

C : H : O = 3 : 3 : 1

Empirical formula is C₃H₃O.

8 0
4 years ago
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