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irinina [24]
2 years ago
9

What observations can you make about this group of people? Name one inference you can make from your observations.​

Chemistry
2 answers:
Stells [14]2 years ago
7 0

Answer:

no no no who are these some look good but are black what is this

Aleonysh [2.5K]2 years ago
4 0

Answer:

they are funny and unite.

Thank You

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Na-23 has 12 neutrons. What is its atomic number
sweet-ann [11.9K]
Atomic number is 11.
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3 years ago
PLZ HELP WILL MARK BRAINLIEST
snow_lady [41]

Answer:

The male cone

Explanation:

The male cones, which produce pollen, are usually herbaceous and much less conspicuous even at full maturity.

3 0
3 years ago
A horizontal row of the periodic table is usually referred to as a ____________
zaharov [31]

the answer is period

8 0
3 years ago
Read 2 more answers
Cierta cantidad de gas ocupa 20 litros sometido a una presión de 1,5 atmósferas. Si lo comprimimos hasta 6 atmósferas, ¿qué volu
Mekhanik [1.2K]

Respuesta:

5 L

Explicación:

Paso 1: Información provista

  • Presión inicial (P₁): 1,5 atm
  • Volumen inicial (V₁): 20 L
  • Presión final (P₂): 6 atm

Paso 2: Calcular el volumen final del gas

Si asumimos temperatura constante y comportamiento ideal, podemos calcular el volumen final del gas (V₂) usando la Ley de Boyle.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1,5 atm × 20 L / 6 atm = 5 L

4 0
3 years ago
Express the concentration of a 0.0320 M aqueous solution of fluoride, F−, in mass percentage and in parts per million (ppm). Ass
denis23 [38]

Answer:

607 ppm

Explanation:

In this case we can start with the <u>ppm formula</u>:

ppm=\frac{mg~of~solute}{Litters~of~solution}

If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of F^-, because the molarity formula is:

M=\frac{mol}{L}

In other words:

0.0320~M=\frac{mol}{1~L}

mol=0.032~M*1~L=0.032~mol

1~L~of~Solution=0.0320~mol~of~solute

If we use the <u>atomic mass</u> of F  (19 g/mol) we can convert from mol to g:

0.0320~mol~F^-\frac{19~g~F^-}{1~mol~F^-}~=~0.607~g

Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:

0.607~g\frac{1000~mg}{1~g}=607~mg

Finally we can <u>divide by 1 L</u> to find the ppm:

ppm=\frac{607~mg}{1~L}=~607~ppm

<u>We will have a concentration of 607 ppm.</u>

I hope it helps!

4 0
3 years ago
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