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S_A_V [24]
3 years ago
9

Plz help me with this plz pt.2

Chemistry
1 answer:
bogdanovich [222]3 years ago
3 0
The answer to your question is A I think
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There are 81 amino acid residues in the precursor molecule of bovine insulin. What is the least number of bases that must be in
Usimov [2.4K]
If you count the methionine expressed for the start codon as part of the precursor protein, then (81+1)*3. (The start codon is expressed, but the stop codon isn't.) 
8 0
4 years ago
Read 2 more answers
How many oxygen atoms are in 1.60 g of quartz? hints?
Naily [24]
Quartz has the formula SiO2
From the periodic table:
mass of oxygen = 16 grams
mass of silicon = 28.0855 grams
Mass of one mole of quarts = 28.0855 + 2(16) = 60.0855 grams

number of moles = mass / molar mass
number of moles = 1.6 / 60.0855 = 0.0266 moles

Each mole of quartz contains Avogadro's number of atoms.
Therefore:
number of atoms in 1.6 g = 1.6 x 6.02 x 10^23 = 1.603 x 10^22 atoms
4 0
3 years ago
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(40 Points) Complete, balance, compute the amounts of the products assuming 100% yield. 10g Na + 10g Oxygen.
Lilit [14]

13.5g

Explanation:

Given parameters:

Mass of Na = 10g

Mass of O₂ = 10g

Unknown:

Mass of products formed = ?

Balanced equation = ?

Solution:

The balanced chemical equation is shown below:

                  4Na       +     O₂     ⇒      2Na₂O

In any reaction, the specie in short supply determines the extent of the reaction.

This reaction is not an exclusion. We need to first determine the specie in short supply and use it to estimate the amount of product since we have a 100% yield which signifies that all was used up.

  let us convert to moles;

    Number of moles of Na = \frac{mass }{molar mass}  = \frac{10}{23} = 0.435mole

 Number of moles of O₂ = \frac{mass}{molar mass} = \frac{10}{32} = 0.313mole

From the given equation;

   4 moles of Na requires 1 mole of O₂;

  0.435 moles of Na will require \frac{0.435}{4} = 0.11 moles

 But the given amount O₂ is 0.313, this is an excess of 0.313 - 0.11 = 0.203moles

We see that Na is the limiting reagent;

   4 moles of Na gives 2 mole of Na₂O

   0.435 moles of Na will give \frac{0.435 x 2 }{4} = 0.22 moles

Mass of Na₂O = number of moles x molar mass = 62 x 0.22 = 13.5g

learn more:

Number of moles brainly.com/question/1841136

#learnwithBrainly

5 0
4 years ago
Calculate the value of ΔG∘rxnΔGrxn∘ for the following reaction at 296 K. Ka = 2.9 × 10–8 and assume Ka does not change significa
oee [108]

Answer:

\Delta G_{rxn}=42.7\frac{kJ}{mol}

Explanation:

In this case, for the dissociation of hypochlorous acid, we know that the acid dissociation constant (Ka) is 2.9x10⁻⁸, which is related with the Gibbs free energy as shown below:

\Delta G_{rxn}=-RTln(K)

But in this case K is just Ka, therefore, at 296 K, it turns out:

\Delta G_{rxn}=-8.314\frac{J}{mol*K}*296K*ln(2.9x10^{-8})\\\\\Delta G_{rxn}=42.7\frac{kJ}{mol}

Such result, means that the reaction is nonspontaneous at the given temperature, it means it is not favorable (not easily occurring).

Best regards.

7 0
3 years ago
A student has a rectangular block. It is 2 cm wide. 3 cm tall and 25cm long. It has a mass of 600 g. First, calculate the volume
Klio2033 [76]

Answer:

The area of the block is 150 cm

Explanation:

8 0
3 years ago
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