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2 years ago

A plane starting from rest accelerates at 3m/s2 for 25s. Calculate the increase in velocity after:

Physics

1 answer:

horsena [70]2 years ago

5 0

Initial velocity=u=0m/s
Acceleration=a=3m/s^2

Time not needed now

Case-1:-

Time=1s
Final velocity=v

$\\ \rm\hookrightarrow v=u+at$

$\\ \rm\hookrightarrow v=0+3(1)$

$\\ \rm\hookrightarrow v=3m/s$

Case-2:-

Time=3s

$\\ \rm\hookrightarrow v=0+3(3)$

$\\ \rm\hookrightarrow v=9m/s$

Case-3:-

Time=25s

$\\ \rm\hookrightarrow v=0+3(25)$

$\\ \rm\hookrightarrow v=75m/s$

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insens350 [35]

Answer:

Explanation:

This is a recoil problem, which is just another application of the Law of Momentum Conservation. The equation for us is:

$[m_av_a+m_ev_e]_b=[m_av_a+m_ev_e]_a$ which, in words, is

The momentum of the astronaut plus the momentum of the piece of equipment before the equipment is thrown has to be equal to the momentum of all that same stuff after the equipment is thrown. Filling in:

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Obviously, on the left side of the equation, nothing is moving so the whole left side equals 0. Doing the math on the right and paying specific attention to the sig fig's here (notice, I added a 0 after the 4 in the velocity value so our sig fig's are 2 instead of just 1. 1 is useless in most applications).

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