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erica [24]
3 years ago
12

A plane starting from rest accelerates at 3m/s2 for 25s. Calculate the increase in velocity after:

Physics
1 answer:
horsena [70]3 years ago
5 0
  • Initial velocity=u=0m/s
  • Acceleration=a=3m/s^2

Time not needed now

Case-1:-

  • Time=1s
  • Final velocity=v

\\ \rm\hookrightarrow v=u+at

\\ \rm\hookrightarrow v=0+3(1)

\\ \rm\hookrightarrow v=3m/s

Case-2:-

  • Time=3s

\\ \rm\hookrightarrow v=0+3(3)

\\ \rm\hookrightarrow v=9m/s

Case-3:-

  • Time=25s

\\ \rm\hookrightarrow v=0+3(25)

\\ \rm\hookrightarrow v=75m/s

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Compute the power output (watts) during one minute of treadmill exercise, given the following: Treadmill grade-10% Horizontal sp
erma4kov [3.2K]

Answer:

c. 981 watts

P=981\ W

Explanation:

Given:

  • horizontal speed of treadmill, v=100\ m.min^{-1}=\frac{5}{3} \ m.s^{-1}
  • weight carried, w=588.6\ N
  • grade of the treadmill, G\%=10\%

<u>Now the power can be given by:</u>

P=v.w

P=588.6\times\frac{5}{3} (where grade is the rise of the front edge per 100 m of the horizontal length)

P=981\ W

6 0
4 years ago
When the distance between two stars decreases by one-third, the force between them
pashok25 [27]

Answer:

the force will increase by a factor 2.25

Explanation:

The gravitational force between the two stars is given by:

F=G\frac{m_1 m_2}{r^2}

where

G is the gravitational constant

m1, m2 are the masses of the two stars

r is the distance between the stars

If the distance is decreased by one-third, it means that the new distance is 2/3 of the previous distance

r'=\frac{2}{3}r

So the new force will be

F'=G\frac{m_1 m_2}{(\frac{2}{3}r)^2}=\frac{9}{4} G\frac{m_1 m_2}{r^2}=2.25 F

So, the force will be 2.25 times the previous value.

4 0
4 years ago
An electron is moving horizontally east in an electric field that points vertically downward. The electric force on the electron
saveliy_v [14]

Answer:

d. )directed upward.

Explanation:

As the electron has a negative charge, when under the influence of an electric field, is subject to an electric force, which direction is the opposite to the direction of the electric field.

This is because the electric field has the same direction that the force on a positive test charge at the same point.

As the electric field points vertically downward, the electric force on the electron (a negative charge) points vertically upward.

So, the statement d. is the one that results to be true.

7 0
3 years ago
At what phase would you expect to find extremely high and low tides?
creativ13 [48]

Answer:

full moon and new moon

4 0
3 years ago
URGENT
Gemiola [76]

Answer:

5.25 J

Explanation:

W = PE = (f)(x)

PE = 35N*0.15m

PE = 5.25 N*m

1 N*m = 1 J

PE = 5.25 J

7 0
3 years ago
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