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kolezko [41]
2 years ago
15

Which option correctly shows the concentration of H3O+ ions in pure water?(1 point)

Chemistry
1 answer:
loris [4]2 years ago
8 0

Answer:

1.0x10^-7 mol/L

You might be interested in
A) ¿Cuáles son las partículas elementales que componen la materia, b) cuál es su ubicación, c) su carga eléctrica?
loris [4]

Las 3 partículas elementales son a) electrón, protón y neutrón. Se encuentran b) electrón en las órbitas electrónicas, el protón y el neutrón están en el núcleo. Sus cargas son c) electrón-negativo; protón-positivo; neutrón-sin carga. (Opción A).

Según el modelo atómico moderno, las partículas elementales que componen la materia son:

  • Electrón, se ubica en las órbitas electrónicas y tiene carga negativa.
  • Protón, se ubica en el núcleo y tiene carga positiva.
  • Neutrón, se ubica en el núcleo y no tiene carga

Las 3 partículas fundamentales son a) electrón, protón y neutrón. Se encuentran b) electrón en las órbitas electrónicas, el protón y el neutrón están en el núcleo. Sus cargas son c) electrón-negativo; protón-positivo; neutrón-sin carga. (Opción A).

Aprende mas: brainly.com/question/22693941

5 0
2 years ago
The units of density are kg/m2. If the density of a liquid is 760.0 kg/m' what is the specific volume? a) 1.316 x 10 m2/kg b) 1.
zlopas [31]

Answer:

The correct answer is: 1.316 . 10⁻³ m³/kg.

Explanation:

The density (ρ) of a substance is the ratio of its <em>mass (m)</em> to its <em>volume (V)</em>. At constant temperature and pressure, its value is constant and it is an intrinsic property of materials. The units of density are kg/m³.

\rho = \frac{m}{V}

The specific volume (ν) of a substance is the ratio of its <em>mass</em> to its <em>volume</em>. We can see that it is the reciprocal of density and an intrinsic property of matter as well. Therefore, the units of specific volume are m³/kg.

\nu = \frac{V}{m}=\frac{1}{\rho }

Given we know the density of the liquid, we can use this relationship to find out its specific volume:

\nu =\frac{1}{\rho }=\frac{1}{760.0kg/m^{3} } =1.316 .10^{-3} m^{3} /kg

6 0
3 years ago
Create an outline to organize your presentation. Write the outline for your presentation in the space provided. You can organize
MrMuchimi
What do u specificity need help with ?
5 0
3 years ago
Element whose atoms have completed their outer energy level are the ____​
umka21 [38]

Answer:

Noble gases

Explanation:

nobles gases have their outer energy level complete

5 0
2 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
2 years ago
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