Explanation:
Let two charges are
, such that,
.............(1)
Distance between charges, r = 3 m
The force of repulsion between them is, F = 0.075 N
We can consider that both charges are positive, so that there exists the force of repulsion. The force of repulsion is given by :



.............(2)
On solving equation (1) and (2) we get :


(b) Now the force of attractive, F = -0.525 N
Let charges are
such that,
.............(3)
Force of attraction is given by :



.............(4)
Now on solving equation (3) and (4) we get :

and

Hence, this is the required solution.