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tekilochka [14]
2 years ago
10

HELP!! ASAP!! PLEASE!!

Chemistry
1 answer:
kvv77 [185]2 years ago
6 0

The bonds that are present in the pictured compound are C −C and C −H.

<h3>What is a bond?</h3>

A bond is that which connects two atoms together. We know that a compound is composed of bonds. There are a number of bonds in a compound. The bonds are always as many as the atoms that need to be linked in the compound.

We know that butane a shown in the image is an alkane. An alkane has carbon - carbon and hydrogen - carbon bonds. There are no multiple bonds in the compound butane.

Thus, the bonds that are present in the pictured compound are C −C and C −H.

Learn more about chemical bond:brainly.com/question/15444131

#SPJ1

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What mass of chloride gas will react with 96.6g of sodium?
Oduvanchick [21]
Molar mass :

Cl₂ =  71.0 g/mol        Na = 23.0 g/mol

<span>2 Na + Cl</span>₂<span> = 2 NaCl
</span>
2 x 23 g Na -------> 71.0 g Cl₂
96.6 g Na ----------> ?

Mass Cl₂ = ( 96.6 x 71.0 ) / ( 2 x 23 )

Mass Cl₂ = 6858.6 / 46

= 149.1 g of Cl₂

hope this helps!

8 0
4 years ago
Describe a procedure to separate a mixture of sugar, black pepper, and pebbles.
ankoles [38]
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3) Now, Add water 'cause we need to dissolve salt with it.

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8 0
3 years ago
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mash [69]

Answer:

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8 0
3 years ago
t 745 K, the reaction below has an equilibrium constant (Kc) of 5.00 × 102. H2 (g) + I2 (g) ⇌ 2 HI (g) If a mixture of 0.10 mol
spayn [35]

Answer : The concentration of HI (g) at equilibrium is, 0.643 M

Explanation :

The given chemical reaction is:

                        H_2(g)+I_2(g)\rightarrow 2HI(g)

Initial conc.    0.10        0.10      0.50

At eqm.        (0.10-x)  (0.10-x)   (0.50+2x)

As we are given:

K_c=5.00\times 10^2

The expression for equilibrium constant is:

K_c=\frac{[HI]^2}{[H_2][I_2]}

Now put all the given values in this expression, we get:

5.00\times 10^2=\frac{(0.50+2x)^2}{(0.10-x)\times (0.10-x)}

x = 0.0713  and x = 0.134

We are neglecting value of x = 0.134 because the equilibrium concentration can not be more than initial concentration.

Thus, we are taking value of x = 0.0713

The concentration of HI (g) at equilibrium = (0.50+2x) = [0.50+2(0.0713)] = 0.643 M

Thus, the concentration of HI (g) at equilibrium is, 0.643 M

8 0
4 years ago
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AnnyKZ [126]

Answer:

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3 years ago
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