If there is 4 of CH2CI2, then there is 8 of CI. There is already 2 in each one and there is 4 sets so 2x4=8
B) To remove inorganic material.
The decay product represented by X : Thorium (Th) : ²³⁴₉₀Th
<h3>Further explanation</h3>
Given
Decay reaction
²³⁸₉₂U ⇒ ⁴₂He + X
Required
The decay product
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles ₀γ⁰
- positron particles ₁e⁰
- neutron ₀n¹
In a decay reaction, <em>the sum of the mass number and atomic number of the elements in the reactants and products must be the same</em>
So the mass number of the element X = 238 - 4 = 234
Atomic number of the element X = 92 - 2 = 90
If we look at the periodic system, then the element with atomic number 90 is Thorium (Th)
Entropy is measure of disorder in system. Higher the disorder, greater the entropy.
Pair 1: NO2 (g) and N2O4 (g)
In the above case, entropy of N2O4 is more as compared to NO2, because N2O4 has more number of bonds as compared to NO2. So large number of vibrational energy levels are available for energy distribution which results in increasing entropy.
Pair 2: CH3OCH3(l) and CH3CH2OH(l)
Above compounds are structure isomers. They have same number of bonds and vibrational energy levels. However, presence of -OH group in CH3CH2OH results in intermolecular interaction via H bonding. This results in an ordered structure in CH3CH2OH as compared to CH3OCH3. Due to this entropy in CH3CH2OH is lower as compared to CH3OCH3.
Pair 3: HCl(g) and HBr(g)
In present case, HBr will have higher entropy as compared to HCl, because of larger number of sub-atomic particles in Br. Also, the higher molecular mass of HBr favors larger entropy.
